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| Subject:
Optics-refractive
Category: Science > Physics Asked by: al3in-ga List Price: $4.50 |
Posted:
16 Sep 2004 16:20 PDT
Expires: 20 Sep 2004 17:27 PDT Question ID: 402261 |
A gypsy's crystal ball has a refractive index of 1.50 and diameter of 8 inch. 1)by the matrix approuch, detrermine the location of its principal points. 2)where will sunlight be focused by the crystal ball? |
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| Subject:
Re: Optics-refractive
From: racecar-ga on 20 Sep 2004 14:20 PDT |
ray matrix for curved dialectric medium:
[1 0 ]
[ ]
[(n1/n2 - 1)/r n1/n2]
convex r>0, concave, r<0
ray matrix for travel through homogenous medium:
[1 d]
[0 1]
We have first a convex interface with n1=1, n2=n, then travel for a
distance of 2r, then a concave interface with n1=n, n2=1. The
matrices go in reverse order, and when we plug in and multiply, the
ray matrix for the ball is:
[2/n - 1 2r/n ]
[ ]
[(2/n - 2)/r 2/n - 1]
Plugging in r=4 and n=1.5, that is
1/6*[2 32]
[-1 2]
The ray vector for a sunbeam a distance D from the axis is [D]
[0]
Run this through the ray matrix and you get 1/6*[2D]
[-D]
From that you find that the focal point (where sunlight is focussed)
is 1/(3tan(1/6)) from the surface of the ball, or 4 + 1/(3tan(1/6))
from the center. That's about 1.98 inches from the surface, or 5.98
inches from the center. |
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