Google Answers Logo
View Question
 
Q: precise barometer measurements ( No Answer,   2 Comments )
Question  
Subject: precise barometer measurements
Category: Science
Asked by: hunnyjenn-ga
List Price: $30.00
Posted: 22 Sep 2004 18:55 PDT
Expires: 22 Oct 2004 18:55 PDT
Question ID: 405089
How would I be able to correct a barometric pressure reading to sea
level pressure by making corrections for temperature, altitude, and
gravity with all correct precision?
Answer  
There is no answer at this time.

Comments  
Subject: Re: precise barometer measurements
From: redhoss-ga on 22 Sep 2004 19:21 PDT
 
Interesting article:
http://www.npl.co.uk/pressure/faqs/adjustment.html
Subject: Re: precise barometer measurements
From: norbertnipken-ga on 01 Oct 2004 13:49 PDT
 
To compensate for altitude you could use the equations of the ISA
(International Standard Atmosphere). According to ISA,  pressure as a
function of altitude is given by:

P = P0*(1 - L*H/T0)^((g*M)/(R*L))

where,

H = (6356*Z)/(6356+Z) [km]
Z =  altitude of your barometer [km]
P0 = 101325  [Pa] (sea-level std. pressure)
T0 = 288.15  [K]
g = 9.80665  [m/sec2]
L =  6.5     [K/km]
R = 8.31432  [J/ mol*K]
M = 28.9644  [g/mol]
 
To calculate the difference in pressure due to altitude, subtract the
standard pressure at altitude (using the above formula) from standard
sea-level pressure (i.e. P0).  Now add this to the actual pressure you
measured at altitude (station-pressure). This will give a pressure
"corrected to sea-level".

As for temperature and gravity, I think this has to do more with the
specific characteristics of the barometer you are using so I can't
really comment on it. (A mercury barometer would probably feel the
effects of temperature and gravity).  It is true that the acceleration
due to gravity changes as you move away from the earth but I don't
think the change is large enough to be of significance in this
calculation (it's not accounted for in the ISA formula).

I'm no meteorologist, so all this might be way-off, but I did build a
electronic weather station so I have done this type of calculation and
it seems to work out alright. (note: the pressure sensor on my weather
station was a semiconductor device).

Important Disclaimer: Answers and comments provided on Google Answers are general information, and are not intended to substitute for informed professional medical, psychiatric, psychological, tax, legal, investment, accounting, or other professional advice. Google does not endorse, and expressly disclaims liability for any product, manufacturer, distributor, service or service provider mentioned or any opinion expressed in answers or comments. Please read carefully the Google Answers Terms of Service.

If you feel that you have found inappropriate content, please let us know by emailing us at answers-support@google.com with the question ID listed above. Thank you.
Search Google Answers for
Google Answers  


Google Home - Answers FAQ - Terms of Service - Privacy Policy