I'm working on an application in Visual Studio 6 which will require
the user to share Windows folders under some circumstances.  In order
to allow the user to set up sharing for a folder, I want to
programmatically open the window folder properties dialog to the
sharing tab.  I can open the properties dialog using this code
snippet:

   SHELLEXECUTEINFO sei;
   ZeroMemory(&sei,sizeof(sei));

   sei.cbSize = sizeof(sei);
   sei.lpFile = "C:\\FNR\\user\\data";
   sei.lpVerb = "properties";
   sei.fMask  = SEE_MASK_INVOKEIDLIST;

   ShellExecuteEx(&sei);

This opens the properties dialog to the "General" tab.  I want to open
to the "Sharing" tab.  How can I do that?

I expect an answer that can be applied to any modern MSFT Windows
system without having to install any third-party development tools or
to jump through any unreasonable hoops.  Thanks.

---

Clarification of Question by iammrjvo-ga on 23 Sep 2004 06:43 PDT

In case it isn't obvious, I'm working in Visual C++.  Thanks again.

You can use this code to open the "Sharing" tab.

	SHELLEXECUTEINFO sei;
	ZeroMemory(&sei,sizeof(sei));

	sei.cbSize = sizeof(sei);
	sei.lpFile = "C:\\TEMP";
	sei.lpVerb = "properties";
	sei.fMask  = SEE_MASK_INVOKEIDLIST;

	ShellExecuteEx(&sei);
	Sleep(250);

	keybd_event(VK_CONTROL, 0, KEYEVENTF_EXTENDEDKEY, 0);
	keybd_event(VK_TAB, 0, KEYEVENTF_EXTENDEDKEY, 0);
	keybd_event(VK_CONTROL, 0, KEYEVENTF_EXTENDEDKEY | KEYEVENTF_KEYUP, 0);