Hi MathTalk,
i have an integral equation problem which i resume in the following PDF file:
http://0201.netclime.net/1_5/X/H/G/Exercise_ANIBA_En.pdf
I hope that's your answer will be excellent as exepected :).
Thanks. |
Request for Question Clarification by
mathtalk-ga
on
20 Oct 2004 04:10 PDT
Hi, ghassane-ga:
In the case you have solved, for the exponential distributions, the
density functions are monotone decreasing from 0 to +oo. I'm
wondering if the application you have in mind supports a similar
assumption.
Is there any additional information about the density functions or
cumulative distribution functions based on them which can be assumed?
regards, mathtalk-ga
|
Clarification of Question by
ghassane-ga
on
20 Oct 2004 06:27 PDT
Hi,
No, the application didn't support similar assumption. In general,
i'll apply it for Gaussian, Exponential, Rayleigh, Nakagami,
log-normal distrinutions.
Thanks.
|
Clarification of Question by
ghassane-ga
on
20 Oct 2004 06:37 PDT
Hi,
i supposes that you already know that cumulative distribution function
is an increasing function which converges in Infinity to 1.
ragrds, ghassane-ga
|
Request for Question Clarification by
mathtalk-ga
on
20 Oct 2004 08:41 PDT
Yes, I'm thinking about a "change of variable" approach that would
simplify some of the expressions and establish some broad conditions
under which a solution r is known to exist (and perhaps be unique).
regards, mathtalk-ga
|
Clarification of Question by
ghassane-ga
on
20 Oct 2004 13:55 PDT
Hi,
I'm sure that there existes a unique solution.
Please follow this link, to see the original form of the equation,
perhaps it will be simpler to found "r" than in the actual form.
http://0201.netclime.net/1_5/G/T/Q/Original_Function.pdf
regards, ghassane-ga.
|
Clarification of Question by
ghassane-ga
on
20 Oct 2004 13:58 PDT
Hi,
can you add the Rician distribution to the other, if you found
solution for the above-mentionned distributions.
thanks.
regards, ghassane-ga.
|
Clarification of Question by
ghassane-ga
on
22 Oct 2004 06:17 PDT
Hi mathtalk,
You can suppose that we have a finite expection E[X] and E[Y].
I know that you have already solved a problem like this one, and
that's why i choose you :).
nice weekend with my problem.
|
Clarification of Question by
ghassane-ga
on
27 Oct 2004 08:43 PDT
Hi MathTalk,
are you still workin in my problem or you forgot it :))
thanks.
|
Request for Question Clarification by
mathtalk-ga
on
27 Oct 2004 13:47 PDT
Well, I've sorted out the equivalence of the three ways you stated the
problem, and I came up with a fourth way of stating it myself that
makes existence/uniqueness more obvious.
As with the other Question you posted, it would probably be a good
time to clarify exactly what is expected in the nature of an Answer.
You've given the closed form solution for the exponential
distributions f_X(x) and f_Y(y). I think it unlikely that for the
list price offered I'd have time to do a proper investigation of all
five other distributions that you named:
Gaussian, Rayleigh, Nakagami, log-normal, Rice
if the intention is to find "closed form" solutions for each.
However if that's what you are hoping to obtain, I'd be agreeable to
open the Question up for other Researchers so that everyone has an
opportunity to try.
regards, mathtalk-ga
|
Clarification of Question by
ghassane-ga
on
27 Oct 2004 15:05 PDT
Hi,
i agree with you. but, how can i open it to other researchers?
|
Request for Question Clarification by
mathtalk-ga
on
27 Oct 2004 15:40 PDT
You just did!
best wishes, mathtalk-ga
|