|
|
Subject:
Astronomy
Category: Science > Astronomy Asked by: glenray-ga List Price: $2.00 |
Posted:
08 Nov 2004 13:07 PST
Expires: 09 Nov 2004 11:43 PST Question ID: 426266 |
What would be the radial velocity of a star if we observe the hydrogen-alpha line (normal wavelength = 6563 A) at a wavelength of 6566 and is it moving toward or away from the earth? |
|
There is no answer at this time. |
|
Subject:
Re: Astronomy
From: guzzi-ga on 08 Nov 2004 19:29 PST |
Shift spectrum is due to velocity towards or away from the observer. Radial velocity of a star superimposes a smear upon that spectrum, one edge rotating away from the observer and the other edge receding. The degree of smear is of course dependent upon the relative plane of rotation. The shift on your example is so small that a simple proportional calculation is almost identical to basing the calculations upon the slightly more complex relativity formula. The speed of light is accepted by the SI international body as 299,792.458 km/s, coincidentally so nearly 300,000 km/s that it is good enough for most calculations. Also commonly used is 186 thousand miles per second. Your wavelength is longer, so the star is receding, by wavelength proportion calculation at 137 km/s (about 493 thousand kilometres per hour or about 308 thousand miles per hour). Best |
Subject:
Re: Astronomy
From: iang-ga on 09 Nov 2004 05:15 PST |
>Radial velocity of a star superimposes a smear upon that spectrum Should that be "Rotational velocity..."? Ian G. |
If you feel that you have found inappropriate content, please let us know by emailing us at answers-support@google.com with the question ID listed above. Thank you. |
Search Google Answers for |
Google Home - Answers FAQ - Terms of Service - Privacy Policy |