The following dosage was used in a clinical trial
"2.0nm 3BrPA in 1x PBS ph 7.5"

BrPA has a molecular weight of 166.92 (almost 167)

I would like to know how this translates into mg or mcg

2.0 nM = 2.0 x 10^-9 mol/ L

2E-9 mol/L  *  166.9 g/mol = 3.338 E-7 g/ L

3.338 E-7 g/L  * 1000 mg/ g =  3.338E-4 mg/ L

3.338 E-4 mg/ L   *  1 L/ 1000 ml

3.338 E-7 mg/ ml   *  1 ml / CC

~ 3.3 E-7 mg/ CC