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Q: How to make a solution ( Answered,   2 Comments )
Question  
Subject: How to make a solution
Category: Science > Chemistry
Asked by: foody-ga
List Price: $10.00
Posted: 30 Nov 2004 07:37 PST
Expires: 30 Dec 2004 07:37 PST
Question ID: 436062
How do I make a 20 gram solution of a 1% solution of Aldehyde C-10 in
Dipropylene Glycol?
Answer  
Subject: Re: How to make a solution
Answered By: livioflores-ga on 30 Nov 2004 23:51 PST
 
Hi foody!!

arsenic-ga gave you a correct answer, my intention posting this answer
is to go further, giving you the tools to calculate the amount of
solute and solvent for any given mass percent concentration solution
to prepare.

"Definition of Mass Percent Concentration
Mass percent concentration is defined as the mass of the solute in
grams multiplied by 100 divided by the mass of the solution in grams.
mass % = mass of solute * (100) / mass of solution "
From "Mass Percent Concentration":
http://members.aol.com/profchm/masspct.html


Note that a P% solution means there is P gram of solute dissolved in
(100-P) grams of solvent. This means that the solute makes up P% of
the total final mass of the solution.


To solve a problem that has this format: "If it is desired to prepare
X grams of a P% of solute B in solvent A" do the following:

You know the total weight of the solution (the desired amount of
solution), it is X grams, just divide this value by 100, you will find
the value of the 1% of the total weight.
The second step is to multiply the value found in the previous step by
P, you will find with this the value of the P% of the total weight
(the amount of needed solute).
At the final step you must subtract the value found in the 2nd step
from the total weight of the solution to find the amount of needed
solvent.


For example, to solve the problem proposed at this question:

-1st step:

X = 20 grams (total weight of desired solution)

1% of X = 20g / 100 = 0.2g


-2nd step:

P = 1

P% of X = 1 * 0.2g = 0.2g  (amount of needed solute)


-3rd step:

Amount of needed solvent = Total weight of solution - Amount of needed solute 

Amount of needed solvent = 20g - 0.2g =
                         = 19.8g


To make a 20 gram solution of a 1% solution of Aldehyde C-10 in
Dipropylene Glycol you must mix 0.2g of Aldehyde C-10 in 19.8g of
Dipropylene Glycol.


----------------------------------------------------------

As reference you can visit the following pages:

"Mass Percent Concentration":
http://members.aol.com/profchm/masspct.html

"Ways of Expressing Concentration of a Solution":
(follow the links)
http://members.aol.com/profchm/conc.html

"Weight Percent (Wt%) Solutions":
http://www.hometrainingtools.com/articles/weight-percent-solutions-science-teaching-tip.html

"Concentrations of Solutions":
http://www.vet.ohio-state.edu/docs/fluids/part1/part1.html

"Weight Percent":
http://dl.clackamas.cc.or.us/ch105-05/weight.htm


----------------------------------------------------------

Search strategy:
solution grams percent


I hope that this helps you. Feel free to use the clarification request
before rate that ahswer, I will gladly respond your requests of
further assistance on this topic.


Best regards
livioflores-ga
Comments  
Subject: Re: How to make a solution
From: winsplit01-ga on 30 Nov 2004 07:59 PST
 
Mix them up mate mix them up.
Subject: Re: How to make a solution
From: arsenic-ga on 30 Nov 2004 13:42 PST
 
Dissolve 200mg decanal (Aldehyde C-10) in 19.8g dipropylene glycol to
make 20g 2% solution. 1kg of this solution contains 20g decanal.

Just out of curiosity, what's the smell of decanal?

:-) As2O3

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