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Q: Probability of winning play for given hand in "jacks or better" poker ( No Answer,   1 Comment )
Question  
Subject: Probability of winning play for given hand in "jacks or better" poker
Category: Computers > Algorithms
Asked by: jacks13-ga
List Price: $50.00
Posted: 21 Jan 2006 10:35 PST
Expires: 10 Feb 2006 19:46 PST
Question ID: 436210
The game is "jacks or better".  Given a particular 5-cards hand (i.e.
10 Clubs, 10 Diamonds, 6 Diamonds, 6 Spades, 4 Spades), there are 32
strategies to proceed, from "replace none" to "replace all". There are
9 standard poker winning hands, from "royal flush" to "jacks or
better".  This creates a 32 x 9 matrix, with S(i,j) being a
probability of using i-th strategy and getting j-th winning hand.  In
the above example S(1,1)=0, since if we hold all cards, there is no
chance of getting "royal flush".  S(1,8)=1, since if we hold all
cards, we already have "2 pairs" (8-th winning hand).
Is there a research or publication that provides an efficient
algorithm for calculating all these probabilities for any hand with
sufficient math justification that can be followed and verified?  I am
not looking for a computer program that provides an answer (there are
quite a few of those), since there is no way to verify calculation. 
Obviously, computer simulation may be set to go through all possible
permutations, but that will take quite some time.
Answer  
There is no answer at this time.

Comments  
Subject: Re: Probability of winning play for given hand in "jacks or better" poker
From: bookface-ga on 25 Jan 2006 13:32 PST
 
http://wizardofodds.com/jacksorbetter

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