You obviously made a mistake in copying the question; parts (1) and
(2) both ask for the fugacity coefficient (f/P) at 200 bars.
To answer parts c) and d), one needs information you haven't given us,
namely the "generalized fugacity coefficient chart" referred to in
part c), and the Lee-Kessler equation of state parameters needed for
part d).
Part a) is trivial. By definition for an ideal gas, the fugacity is
equal to the partial pressure. f/P = 1
Part b) is asking for the fugacity coefficient for a nonideal gas that
obeys the van der Waals equation of state when the size parameter (b
parameter) dominates, and the intermolecular forces are negligible (a
parameter = 0).
Let g = f/P (g is the fugacity coefficient, usually written as a lower
case Greek gamma). For any real gas,
(d ln(g)/dp)_T = v/RT - 1/p, [look this up in your textbook]
where (d ln(g)/dp)_T means the partial derivative of the ln of the
fugacity coefficient with respect to pressure at constant temperature.
Integrating this, we get:
ln(g) - ln(g0) = Integral from p=0 to P { (v/RT -- 1/p) dp},
where g0 is the fugacity coefficient at P=0 bars. But the fugacity is
defined to be equal to the pressure as P-> 0, so ln(g0) =ln(P/P) = 0.
We are given that v = RT/p + b. Substituting this into the integrand
above, you'll find that the RT/p terms cancel out, and we are left
with:
ln(g) = Integral from p = 0 to P {b/RT dp}
= b/RT*(P-0) = bP/RT
exponentiating both sides yields the desired result:
g = f/P = exp(bP/RT)
or, noting that from the equation of state that P/RT = 1/(V-b)
g = f/P = exp(b/(V-b))
You need to plug in the particular values of b, T, and P (or V)
corresponding to the conditions asked about in the problem. Note that
b is a function of T. |