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Subject:
Algebra - - Two unknowns & two equations
Category: Science > Math Asked by: bravelobster-ga List Price: $10.00 |
Posted:
23 Jul 2002 06:43 PDT
Expires: 22 Aug 2002 06:43 PDT Question ID: 44114 |
I'm having difficulty determining a solution for (x + y) given the two equations below: c1 = 1/2*c2*(A*x^2 + B*y^2) and A*x = B*y All values are constants except for x & y. |
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Subject:
Re: Algebra - - Two unknowns & two equations
Answered By: websearcher-ga on 23 Jul 2002 07:14 PDT Rated: |
Hi bravelobster-ga: The answer to you question is: (x+y) = +- (sqrt(2) * sqrt((c1*A)/(c2*B^2 + c2*B*A)) * (B+A)) / A where "+-" means plus or minus (i.e., two separate answers, one poisitive, one negative) "sqrt( )" means the square root of the value in parenthases. (I have attempted to attach a character-based rendering of this solution to the end of this message, but I have no idea how it will come through in the final posting.....) How did I get the answer? I just happened to be working with Maple (a symbolic algebra software package) at the time and was able to solve it usign that. You can find more information about Maple at: http://www.maplesoft.com If you need further clarification of the answer, please let me know. Thanks. websearcher-ga character-based rendering: 1/2 / c1 A \1/2 2 |--------------| (B + A) | 2 | \c2 B + c2 B A/ x + y = -------------------------------- A 1/2 / c1 A \1/2 2 |--------------| (B + A) | 2 | \c2 B + c2 B A/ x + y = - -------------------------------- A |
bravelobster-ga
rated this answer:
A correct yet overly complex answer that needed to be simplified further. |
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Subject:
Re: Algebra - - Two unknowns & two equations
From: aditya2k-ga on 23 Jul 2002 07:54 PDT |
I've come up with a solution in terms of y. I've verified this solution by substituting numbers. The solution is in graphic problem, as its easier to understand compared to seeing text. Solution can be found at http://scion.web1000.com/googlesol1.jpg |
Subject:
Re: Algebra - - Two unknowns & two equations
From: aditya2k-ga on 23 Jul 2002 08:04 PDT |
Websearcher's answer is correct, but the equation can be reduced further to the form which can be seen in graphic form at http://scion.web1000.com/googlesol2.jpg Cheers, aditya2k |
Subject:
Re: Algebra - - Two unknowns & two equations
From: bravelobster-ga on 23 Jul 2002 09:12 PDT |
Thank you 'aditya2k-ga' for reducing the answer given by 'websearcher-ga' to a simpler form. I couldn't have done that myself. |
Subject:
Re: Algebra - - Two unknowns & two equations
From: tne-ga on 20 Aug 2002 19:38 PDT |
1. c1 = half c2(Ax^2 + By^2) 2. Ax = By from 2. => Bxy = Ax^2 => x^2 = (B/A)xy => Axy = By^2 => y^2 = (A/B)xy substitute in 1. => c1 = half c2(A + B)xy xy = (2*c1) / (c2(A + B)) => x^2 = 2*(B/A) * c1 / (c2(A + B)) => y^2 = 2*(A/B) * c1 / (c2(A + B)) => x+y = sqrt(2c1/c2) * sqrt((A+B)/AB) |
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