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Subject:
^Probability question
Category: Computers Asked by: dai_hop-ga List Price: $2.00 |
Posted:
07 Feb 2006 11:21 PST
Expires: 09 Mar 2006 11:21 PST Question ID: 442702 |
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There is no answer at this time. |
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Subject:
Re: ^Probability question
From: hfshaw-ga on 07 Feb 2006 16:27 PST |
What do you mean by "accessed in a serial manner"? Do you mean that the first of the 5 questions is chosen at random from the 2 available, and then the remaining 4 questions are simply the ones that follow in database order after that first random choice, or do you have something else in mind? Are you only interested in the probability that all 5 questions are duplicated on the two instances of the test, or are you also interested in the probability of N matches (N=1,2,3,4,5)? |
Subject:
Re: ^Probability question
From: ansel001-ga on 08 Feb 2006 00:46 PST |
I'm not sure what you mean by "accessed in a serial manner" either so I'll confine my comment to when the questions are "accessed in a random manner". The chance of getting the same 5 questions again with the order unimportant is: (5/20) x (4/19) x (3/18) x (2/17) x (1/16) = 1/15504 = 6.4499484 x 10^(-5) If you want the same 5 questions in the same order the chances are: (1/20) x (1/19) x (1/18) x (1/17) x (1/16) = 1/1,860,480 = 5.374957 x 10^(-7) |
Subject:
Re: ^Probability question
From: dai_hop-ga on 08 Feb 2006 03:40 PST |
When I say "accessed in a serial manner" i mean that the selection process starts at the first record and then selects five records one after another. It is my reckoning that these probabilites are as follows... What is the probability that the second quiz will contain the same questions as the first quiz? 100% probabilty If the second quiz contains the same questions as the first. What is the probability that their order will be the same? 100% probabilty ...because although the database contains 20 questions, only the first five questions are being selected. Am I correct? If so, would it be possible for you to show me the workings please? |
Subject:
Re: ^Probability question
From: chisophugis-ga on 16 Feb 2006 16:50 PST |
tHAT IS EASY THE PROBABILITY IS 1:1,978,234 FOR THEM TO CONTAIN THE SAME QUESTIONS AS THE FIRST AND THE PROBABILITY IS 1:12,452,907,451 FOR THEM TO CONTAIN THE SAME QUESTIONS IN THE SAME ORDER |
Subject:
Re: ^Probability question
From: manuka-ga on 28 Feb 2006 00:35 PST |
I don't really see why this question is so difficult to interpret... If the database records are accessed in a serial manner, then the first time the quiz is run it will contain questions 1, 2, 3, 4 and 5 (in order). The next time it will contain 6, 7, 8, 9, and 10 (in order), and so on. On the assumption that the average number of users at any one time is significantly more than 1, each time a given user runs the quiz they are essentially selecting at random between the following ordered question sets: 1, 2, 3, 4, 5 6, 7, 8, 9, 10 11, 12, 13, 14, 15 16, 17, 18, 19, 20 Thus there is a 25% chance that they will get the same set of questions, and if they do there is a 100% chance that the order will be the same. With random access, ansel001 is correct for the first part of the question. For the second part, note the clause that says "If the second quiz contains the same questions as the first..." - so we are assuming that we have the same five questions; the probability of getting them in the same order is just (1/5) * (1/4) * (1/3) * (1/2) * 1 = 1/120. (Or, if you know permutation theory, the number of orders is 5P5 = 5! = 120, so the probability of getting the same one is 1/120.) |
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