|
|
Subject:
protein concentration
Category: Science > Biology Asked by: bata-ga List Price: $10.00 |
Posted:
23 Jul 2002 22:07 PDT
Expires: 22 Aug 2002 22:07 PDT Question ID: 44439 |
how can i determin protein concentration using tha amide bond absorbtion at 220nm. what is the absorbation coeffiecent at this weavelength? |
|
Subject:
Re: protein concentration
Answered By: nealc-ga on 25 Jul 2002 09:14 PDT |
After searching the web over I realized this is not an easy task. The extinction coefficient at a wavelength of 280 is unique for each protein and depends on the amount of tyrosine, tryptophan and cystine residues in the protein. The assumption is the spectral contributions of these amino acids at 280 nm do not differ significantly in the native form of the protein, relative to the denatured form. The following url is a short discussion of how to calculate the extinction coefficient of a protein if you know the number of those three amino acids in the protein. http://www.basic.nwu.edu/biotools/proteincalc.html#helpexco However in further searching I found a url that quotes a Methods in Enzymology article. In this article they talk about calculating the extinction coefficient at 205 nm. The url is below. They reference the articles they got the calculations from. It seems easy enough if you have a UV spectrophotometer, quartz cuvettes, and some Brij 35. There are some errors in your coefficient if your protein has a lot of phenylalanine in it. http://www.ruf.rice.edu/~bioslabs/methods/protein/absext.html Hope that helps. Nealc-ga |
|
Subject:
Re: protein concentration
From: tehuti-ga on 24 Jul 2002 05:12 PDT |
As far as I understand, protein concentration is determined by measuring tyrosine residues at 280 nm, while determination of amide bonds at 220 nm is used to investigate structural changes in the protein backbone. |
Subject:
Re: protein concentration
From: nawal-ga on 09 Aug 2002 13:53 PDT |
What I feel is about concentration of protein quantitatively can be determined using TNBSA titration method. That can give better and more correct value of concentrations. |
If you feel that you have found inappropriate content, please let us know by emailing us at answers-support@google.com with the question ID listed above. Thank you. |
Search Google Answers for |
Google Home - Answers FAQ - Terms of Service - Privacy Policy |