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Q: Physical Science ( No Answer,   4 Comments )
Question  
Subject: Physical Science
Category: Science
Asked by: musicfan-ga
List Price: $2.00
Posted: 23 Feb 2006 05:30 PST
Expires: 24 Feb 2006 11:39 PST
Question ID: 448745
An object has a mass of 615 grams and a volume of 105cm^3. What is the
density of the object?
Answer  
There is no answer at this time.

Comments  
Subject: Re: Physical Science
From: rainbow-ga on 23 Feb 2006 06:18 PST
 
musicfan,
If you were not fully satisfied, you could ask for clarification
before rating my answer. I don't understand why you were not fully
satisfied.

Rainbow~
Subject: Re: Physical Science
From: sachina2005-ga on 23 Feb 2006 06:50 PST
 
Yes, I agree with the person who has answered. This answer can not be made better
Subject: Re: Physical Science
From: argenta-ga on 23 Feb 2006 07:13 PST
 
And considering that their homework is being being answered for them.
Subject: Re: Physical Science
From: qed100-ga on 23 Feb 2006 08:43 PST
 
It just boils down to something like this:

   Suppose you have a box, with edges each 1 foot long. So it's a box
with a volume of 1 x 1 x 1 = 1^3, or, 1 cubic foot (1 ft^3). Now
suppose you put in some marbles, and we're way out in space,
weightless, so the marbles can all float about inside the closed box
and spread out evenly. If I put in 1 marble, how many marbles per
cubic foot is that? It is, of course, 1 marble per cubic foot, or,
1/ft^3. That's the density of marbles, 1/ft^3.

   Now let's put in more marbles. Put 10 marbles into the same box.
What's the density? It's 10/ft^3. It has a density of 10 marbles per
cubic foot.

   But each marble has a property called "mass", which effectively is
a measure of how hard it is to change its velocity by pushing on it.
But whatever mass ultimately is, you know that each marble hass mass.
So by having a certain density of marbles per volume of space -a
marble density- you also have a mass density.

   Let's say that each marble has a mass of 1 ounce. (Abbreviated 1
oz.) One marble constrained within the box gives the box a mass
density of 1 oz/ft^3. 10 marbles = 10 oz and the volume has a mass
density of 10 oz/ft^3.

   But whatever the amount of mass and the amount of volume, to get
mass density all you need do is divide mass (m) by volume (v): m/v.

   And it's the same in any system of units. The units in your problem
are grams (mass) and centimeters (distance), with volume being c^3.
Given mass = 615 grams, and volume = 105 cm^3, what then is the mass
density? It is 615/105 ~ 5.86 g/cm^3.

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