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Q: algebra ( Answered,   0 Comments )
Question  
Subject: algebra
Category: Reference, Education and News > Education
Asked by: haylo-ga
List Price: $2.00		 Posted: 06 Jan 2005 16:59 PST
Expires: 05 Feb 2005 16:59 PST
Question ID: 453252 
solve for x in the following equation: log 10(2x+1)-log 10 (x+1)=2
Answer  
Subject: Re: algebra
Answered By: livioflores-ga on 06 Jan 2005 20:39 PST
 
Hi!!


log10 (2x+1)-log10 (x+1) = 2 <==> log10 [(2x+1)/(x+1)] = 2 <==>

<==> 10^2 = (2x+1)/(x+1) <==> 100*(x+1) = (2x+1) <==>

<==> 100x + 100 - 2x - 1 = 0 <==> 98x + 99 = 0 <==>

<==> 98x = -99 <==> x = -99/98


x = -99/98 = -1.010204081632653


Hope that this helps.

Regards.
livioflores-ga
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