Consider a point-to-point link 2 km in length. At what bandwidth would
propagation delay (at a speed of 2 x 10^8 m/s) equal transmit delay
for 100-byte packets? What about 512-byte packets?

Hi!!


Propagation delay = Distance / Propagation Speed =
                  = 2000 m / (2 * 10^8) m/s = 10^-5 s

Bandwidth = Size of packet / Transmit delay =
          = (100 * 8) bits / 10^-5 s =
          = 8 * 10^7 bits/s = 
          = 80 Mbps

If we have 512-byte packets:



Bandwidth = Size of packet / Transmit delay =
          = (512 * 8) bits / 10^-5 s =
          = 4.096 * 10^8 bits/s = 
          = 409.6 Mbps

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I hope this helps you. 

Regards.
livioflores-ga

Hi livioflores-ga,

This is just to tell you that your answers are great. look forward to
working with you again.