|
|
Subject:
Mathematical max capacity of 2" spheres in 100.2 cubic feet
Category: Miscellaneous Asked by: anamarie1-ga List Price: $2.00 |
Posted:
26 Jul 2002 15:00 PDT
Expires: 25 Aug 2002 15:00 PDT Question ID: 45574 |
|
Subject:
Re: Mathematical max capacity of 2" spheres in 100.2 cubic feet
Answered By: ukiguy-ga on 26 Jul 2002 15:46 PDT |
Dear anamarie, Since this is not the kind of question that is easily found on the web, I found the answer mathematically. If the volume is 100.2 cubic feet, that means that the height, base, and length of the cube is about 4.6447 feet: length*height*base=area 4.6447*4.6447*4.6447=100.2 cubic feet Now I converted 4.6447 into inches: 4.6447*12=55.7364 inches If the diameter of the balls is two inches, this means that they take up as much room as a two by two by two square. I found how many balls would fit in length: 55.7364 inches (length)/ 2 inches (diameter of ball)= 27.8682 balls Since the base and the height of the cube is the same, the same number of balls will fit: base:27.8682 balls height:27.8682 balls length:27.8682 balls Now I found how many balls would fit in the cube: base*height*length=volume 27.8682*27.8682*27.8682= 21,643.4632946 (rounded 21,643) 21,643 two inch balls can fit into 100.2 cubic feet. Thanks for the question! Best regards, ukiguy |
|
Subject:
Re: Mathematical max capacity of 2" spheres in 100.2 cubic feet
From: googlebrain-ga on 26 Jul 2002 16:42 PDT |
For Square packing, the number given in the answer is correct. However, for an optimum packing scheme, we can do better. The optimum packing density for spheres is .7405 (face-centered cubic lattice) http://mathworld.wolfram.com/SpherePacking.html (1728 cubic inches/cubic foot) * (100.2 cubic feet/2002 Chevy TrailBlazer LT) = 173145.6 cubic inches/2002 Chevy TrailBlazer LT (173145.6 cubic inches/2002 Chevy TrailBlazer LT) * .7405 (sphere packing density) = 128214.3 cubic inches/2002 Chevy TrailBlazer LT (useable volume) (128214.3 cubic inches/2002 Chevy TrailBlazer LT) / (4.19 cubic inches/Antenna Ball) (approximate volume of a 2" sphere) = 31348.23 Antenna Balls This is a theoretical maximum. The number in your particular 2002 Chevy TrailBlazer LT will be some amount smaller, but there's no way to know how much. Also there has been some rounding in my calculations, but nothing drastic. Additional Links: http://www.ics.uci.edu/~eppstein/junkyard/spherepack.html http://www.sciencenews.org/sn_arc98/8_15_98/fob7.htm Search Strategy: sphere packing ://www.google.com/search?sourceid=navclient&q=sphere+packing Kepler Conjecture ://www.google.com/search?sourceid=navclient&q=Kepler+Conjecture |
Subject:
Re: Mathematical max capacity of 2" spheres in 100.2 cubic feet
From: googlebrain-ga on 26 Jul 2002 16:44 PDT |
Of course, my answer should have been 31348.23 Antenna Balls/2002 Chevy TrailBlazer LT. I'm so bad with units like that :) |
Subject:
Re: Mathematical max capacity of 2" spheres in 100.2 cubic feet
From: expertlaw-ga on 28 Jul 2002 09:02 PDT |
So, if you win the contest do you get the SUV? (Just a wild stab in the dark.) If this *is* for a contest, recall that the interior space does not necessarily account for the presence of seats and other components which intrude on that interior space. That is, if the vehicle were gutted the answer above is probably a decent estimate, but if they have filled an actual vehicle with antenna balls and you have to guess "how many" you have to take into account the presence of objects within the vehicle. |
If you feel that you have found inappropriate content, please let us know by emailing us at answers-support@google.com with the question ID listed above. Thank you. |
Search Google Answers for |
Google Home - Answers FAQ - Terms of Service - Privacy Policy |