Is it possible to use the value of a variable as the first parameter
to a list() command?

I'm trying the following with no success - I did have the variables
hardcoded in the list command - but I'd like to be able to make this
variable too if possible - can it be done simply? The only way I can
think of is creating the php script on the fly and running that, which
I'd rather not do?

<?php

// explode string into a structured record

$temp = '$title,
$first_name,
$surname,
$address_line1,
$address_line2,
$address_line3,
$address_line4,
$address_line5,
$postcode';

echo $temp;

list(

//define record structure

${$temp}

) = explode($file_delimiter,$buffer);

echo $title;
?>

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Clarification of Question by document123-ga on 19 Jan 2005 09:36 PST

Vladimir,

Perfect. Thank you very much.

That had me stumped all afternoon. Are you a researcher - if so, post
this as your answer.

---

Clarification of Question by document123-ga on 20 Jan 2005 02:43 PST

Vladimir

I mailed GA support today saying what a great job you'd done.

Thanks very much for your help - no doubt I may have other things to
ask you in future....

You can use the eval() function to execute code that was constructed dynamically.

http://www.php.net/manual/en/function.eval.php

Vladimir

For example this should do the trick:

$temp = '$title,
$first_name,
$surname,
$address_line1,
$address_line2,
$address_line3,
$address_line4,
$address_line5,
$postcode';

eval('list('.$temp.') = explode($file_delimiter,$buffer);');


Vladimir

I'm not a researcher. If you want to help me become one, you can
e-mail answers-support@google.com saying that vladimir-ga helped you
and you think he would make a good researcher. :)

Vladimir