Calculate the ionic strength of magnesium sulphate concentration = 0.025 mol/l

Hi!!


magnesium sulfate = Mg(SO4)  where (SO4) is the sulfate ion.

The possible ions in the solutions are:

Mg++ and (SO4)--, then the valence factors are 2 for both ions.

Their concentrations are both 0.025 mol/l.

Then if I is the ionic strength:

I = 1/2 * (0.025 * 2^2 + 0.025 * 2^2) =
  = 1/2 * (0.100 + 0.100) =
  = 0.100


For references see:
"Chemical Reactivity":
http://www.science.uwaterloo.ca/~cchieh/cact/applychem/reactivity.html

"Solubility Products":
http://www-chem.ucdavis.edu/2B/10SolubilityProduct.pdf


I hope that this helps you. Feel free to request for a clarification
if you need it before rate this answer.

Best regards.
livioflores-ga