Calcuate the force of gravity between the earth (mass=6x10to the
24power kg) and the sun (mass=2x10 to the 30power kg, distance =1.5x10
to the 11power m)

while the specific answer is a $2 question, proof is not, in my
opinion a $2 question.

Fg = GMm/r^2=G*(2E30)*(6E24)/(1.5E11)^2

here is the full prof i think its right because i learn it three years
ago i dont know its 100% right or not because to pats for me to learn

F=(G*m1*m2)/d^2
F=((6.67*10^-11)*(6*10^24)*(2*10^30))/(1.5*10^11)^2
F=80.4*10^43/((1.5*10^11)^2)
F=80.4*10^43/1.3225*10^22
F=60.79*10^21 

G=isthe gravitational constant its value is (6.67*10^-11)
^=means raise to the power

i have write the formula above check it again and culculate it again
for confermattion okay

i dont know how to add in answer so i add comment

Bila, that looks like some mighty fine math there.

I don't suppose you'd be willing to do it again to show the
centrifigal (i probably butchered that word) force of the earth given
velocity, radius of its orbit and mass?

I'd enjoy seeing how close you can get the 2 forces without basing 1
off of the other.

Fc = mv^2/r, where Fc = centrifugal force, m = mass, v = velocity, and r = radius

I think you have a math error, bilalarshad.

(1.5*10^11)^2 does not equal 1.3225*10^22

Rather, it equals 2.25*10^22

Taking this into account results in F = 3.557 x 10^22 (Note the units
are kg*m/sec^2 or Newtons)

Calculating the centripetal force, and using v_earth = 29.8 km/s (the
commonly accepted value by astronomers everywhere), we get:

F = m*v^2/r
  = 6 x 10 ^24 * 29800^2 / 1.5 x 10^11
  = 3.552 x 10^22 N

Theoretically, this force should equal the gravitational force between
earth and the sun.  In reality, the two forces are exactly equal. 
Proof of this can be obtained by demonstrating that earth is currently
orbiting the sun.  Since we used rounded figures, the numbers are only
equal to 3 significant digits.