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Subject:
heat
Category: Science > Physics Asked by: daisy001-ga List Price: $2.00 |
Posted:
14 Feb 2005 20:11 PST
Expires: 16 Mar 2005 20:11 PST Question ID: 474699 |
If you wanted to warm 100 kg of water by 20 degrees Celsius for your bath, how much heat is required? (Calories, Joules) |
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Subject:
Re: heat
Answered By: livioflores-ga on 14 Feb 2005 21:25 PST |
Hi!! The specific heat is the amount of heat per unit mass required to raise the temperature by one degree Celsius at constant atmospheric pressure. The specific heat of water is 1 calorie/gram*°C = 4.186 joule/gram*°C i.e., 1 calorie is needed per degree Celsius (or Kelvin) of temperature change for 1 gram of liquid water. Q = c * m * (Tf - T0) where: Q = change in heat energy or heat added to the sample (if negative heat substracted); c = specific heat; m = mass of the sample; (Tf - T0) = final temp less initial temp = change in temperature of sample . Note that the above formula does not apply if a phase change is encountered, because the heat added or removed during a phase change does not change the temperature. Now the problem: We have 100 kg of water, so we have 100,000 grams of water, and we want to raise its temperature 20ºC: Q = unknown; c = 1 cal/g*°C = 4.186 joule/g*°C ; m = 100,000 g ; (Tf - T0) = 20ºC Then: Q = 1 cal/g*°C * 100,000 g * 20ºC = = 2,000,000 calories Q = 4.186 joule/g*°C * 100,000 g * 20ºC = = 8,372,000 joules The required heat is 2,000,000 calories or 8,372,000 joules. I hope that this helps you. Regards. livioflores-ga |
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Subject:
Some facts
From: jesserhaakenson-ga on 14 Feb 2005 21:27 PST |
Your answer relates to the specific heat of a substance, in this case water. This is the amount of energy required to produce a 1°C temperature change per unit of mass. * For water, you need about 4184 joules to raise the temperature of 1 kg water 1°C. * Also, 1 calorie of heat is required to raise temperature of one gram of water by 1 degree Celsius. 1 calorie is 4.184 joules So, if you had 100kg of water and wanted to raise it 20 deg C. Your looking at about 100kg*20deg*4184 = 8,368,000 Joules. Hope this helps. Jesse |
Subject:
Re: heat
From: racecar-ga on 15 Feb 2005 14:04 PST |
Calories, written with a big C, usually means kilocalories, (that's the kind of Calories used to measure the energy content of food) so in this unit, the answer is 2000 Calories (which is about 1 day's worth of food). |
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