The following is a simplified mechanism for predicting O3 formation in
photochemical smog systems:

HC+OH ? a RO2+P	, k1		Hydrocarbon loss and product formation

P+OH ? b RO2+Loss, k2		Product Loss

P+hv ? c RO2+Loss. kp		Product Photolysis

RO2+NO ?NO2+Loss, k3		NO Photooxidation

NO2+hv?NO+O3, k4 forward	Photostationary State
	      k5 backward

Everything?Loss, kd		Dilution

In this mechanism HO2 radicals are lumped up with RO2, and, to a first
approximation, all RO2 are assumed to react with NO. This mechanism
does not predict the OH concentration, taking instead the quantity
k1[OH]=M  as an input hydrocarbon reactivity parameter.

Show that the mechanism can be used to predict the number of net NO
photo oxidations produced per hydrocarbons consumed,

d([NO]-[O3]) / d[HC] = (m(a[HC]+b (k2/k1) [P])+c kp[P]+kd([NO]-[O3])) / (ma+kd)[HC]

Use of the quantity [NO]-[O3] as net NO oxidized effectively cancels
out the photostationary state; thus ozone is simply ?negative nitric
oxide?