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Q: 25 Algebra Problems for \$50!!! ( Answered ,   0 Comments )
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 Subject: 25 Algebra Problems for \$50!!! Category: Miscellaneous Asked by: liquideet-ga List Price: \$50.00 Posted: 27 Feb 2005 13:00 PST Expires: 29 Mar 2005 13:00 PST Question ID: 481898
 ```I need 25 questions answered before 11:00 P.M. CST. The problems range from multiplication, division, facatoring, reducing to lowest terms, simple word problems, etc.``` Clarification of Question by liquideet-ga on 27 Feb 2005 13:02 PST `I forgot to post the questions... http://www.michaelmayhew.net/algebra.doc`
 Subject: Re: 25 Algebra Problems for \$50!!! Answered By: omnivorous-ga on 27 Feb 2005 15:12 PST Rated:
 ```Liquideet ? These questions & answers don't format as easily here on Google Answers, so I?ve loaded a Word document file here for you which can handle the Microsoft Equation editor: http://www.mooneyevents.com/algebra2005.doc And the answers are posted below: 1. Perform the indicated operations and simplify: (2x2 - 3x + 12) - (2x2 +2x -6) = 2x2 - 3x + 12 - 2x2 - 2x + 6 = 18 ? 5x 2. Multiply: a^3*b^3(a^2*b^3c) = Multiplication of exponentials results in addition of exponents: a^5b^6c 3. Divide: x^9/x^16 Division of exponential terms is done via subtraction (numerator ? denominator): x^-7= 1/x^7 4. Multiply (3x + 7)(x2 - 2x +3) = 3x3 ? 6x2 + 9x + 7x2 -14x +21 = 3x3 + x2 - 5x + 21 5. Word Problem: The sum of 15 and twice a number is 41. What is the number? 15 + 2x = 41; 2x = 26; x = 13 6. Square: (b - 12)^2 = (b-12) * (b-12) = b^2 -12b -12b +144 = b^2 - 24b +144 7. Divide: (14x^4y^9)/(7x^3y^5) = 2xy^4 8. Plug In P = 3100 r = .05 t = 5 A = P(1 + rt) = 3100(1 + 0.25) = 3,875 9. Solve for x: 3(x + 2) = 4x; 3x +6 = 4x; 6 = x 10. Solve for y: 3(by +c) = 9; by + c = 3; by = 3 ? c; y = (3-c)/b 11. Function Problem: Given that f(x) = 3x + 7, find f(7). f(7) = 21 + 7 = 28 12. Slope Problem: Given coordinates (x1 = 2, y1 = 4) and (x2 = 4, y2 = -1), find the slope of the line. Slope = (y2 ? y1)/(x2 ? x1) = (-5)/2 = - 2.5 13. Factor: x2 - x - 90 = (x ? 10)(x+9) 14. Reduce to lowest terms: (x-2)(x+2)/(x+5)(x-2) = (x+2)/(x+5) 15. Solve for x and y using the addition method: 2x + 3y = -6 x - 3y = 6 3x = 0; x = 0 16. Solve for x and y using the substitution method: -2x + y = 3 - x + y = 2 y = 2 + x ; -2x + 2 + x = 2 ; -x = 0 ; x = 0 17. Simplify: (10^-9)^1/3 = 10^-9*1/3 = 10^-3 This can also be written as 1/10^3 18. Solve for x: (7x + 1)^1/2 = 6; 7x + 1 = 6^2 7x = 35; x = 5 19. Solve for x: x2 + 4x - 21 = 0 (x + 7)(x ? 3) = 0 x = 3, -7 20. Solve using the quadratic formula: x2 + 12x - 45 = 0 In an equation with the form ax^2 + bx + c = 0, we add (b/2a)^2 to each side: the ultimate solution being: X = [-b +- (b2 ? 4ac)^1/2]/2a ; x = [-12 +- (144 ? 4*(-45))^1/2]/2 = [-12 +- (324)^1/2]/2 = [-12 +- 18]/2; x = 6/2 = 3; x = -30/2 = -15 21. Solve for x: x/90 = 2/30 x = (90 * 2)/30 = 6 22. Solve for x: x^2 = 144 x^2 ? 144 = 0; (x ? 12) (x + 12) = 0 x = -12, 12 23. Change to logarithm form: 10^2 = 100 Google has a calculation function that aids this simply by entering log 100 in the Google search window: log 100 = 2 2 = log (base 10) 100, which is commonly written 2 = log10 100 24. Solve for x: e^x = 12 e = 12 1/x ; if we use e as the natural log, 2.7183 we can solve for x; 2.7183 = natural ln 12 = 2.4849 Again, you can use the Google to figure the natural ln of 12 by typing ?ln 12? into the search window. 25. Solve for x: 10^x = 10,000 10^1 = 10 10^2 = 100 10^3 = 1,000 10^4 = 10,000 10^100 = Googol Obviously x = 4 Alternately you can take log (base10) of 10,000 = 4 If there are any questions or confusion over format, please let me know. Google search strategy: Natural logarithm e Quadratic equation Best regards, Omnivorous-GA```
 liquideet-ga rated this answer: `Great Answer! Great Explanation! Great Comments! A+`

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