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Q: 25 Algebra Problems for $50!!! ( Answered 5 out of 5 stars,   0 Comments )
Question  
Subject: 25 Algebra Problems for $50!!!
Category: Miscellaneous
Asked by: liquideet-ga
List Price: $50.00
Posted: 27 Feb 2005 13:00 PST
Expires: 29 Mar 2005 13:00 PST
Question ID: 481898
I need 25 questions answered before 11:00 P.M. CST.  The problems
range from multiplication, division, facatoring, reducing to lowest
terms, simple word problems, etc.

Clarification of Question by liquideet-ga on 27 Feb 2005 13:02 PST
I forgot to post the questions... http://www.michaelmayhew.net/algebra.doc
Answer  
Subject: Re: 25 Algebra Problems for $50!!!
Answered By: omnivorous-ga on 27 Feb 2005 15:12 PST
Rated:5 out of 5 stars
 
Liquideet ?

These questions & answers don't format as easily here on Google
Answers, so I?ve loaded a Word document file here for you which can
handle the Microsoft Equation editor:
http://www.mooneyevents.com/algebra2005.doc

And the answers are posted below:

1.  Perform the indicated operations and simplify:
(2x2 - 3x + 12) - (2x2 +2x -6) = 

2x2 - 3x + 12 -  2x2 - 2x + 6 = 18 ? 5x

2.  Multiply:
a^3*b^3(a^2*b^3c) =	

Multiplication of exponentials results in addition of exponents:

a^5b^6c

3.  Divide:
x^9/x^16

Division of exponential terms is done via subtraction (numerator ? denominator):

x^-7= 1/x^7 
	

4.  Multiply
(3x + 7)(x2 - 2x +3) =	

3x3 ? 6x2 + 9x + 7x2 -14x +21 = 3x3 + x2 - 5x + 21


5.  Word Problem:
The sum of 15 and twice a number is 41.  What is the number?

15 + 2x = 41; 2x = 26; x = 13
		
6.  Square:
(b - 12)^2 = (b-12) * (b-12) = b^2 -12b -12b +144 = b^2 - 24b +144

7.  Divide:

(14x^4y^9)/(7x^3y^5) = 2xy^4

8.  Plug In 
P = 3100                                   
r = .05
t = 5
A = P(1 + rt) =	 3100(1 + 0.25) = 3,875	

9.  Solve for x:
3(x + 2) = 4x; 3x +6 = 4x; 

6 = x 

10.  Solve for y:
3(by +c) = 9; by + c = 3; by = 3 ? c; 

y = (3-c)/b	

11.  Function Problem:
Given that f(x) = 3x + 7, find f(7).	

f(7) = 21 + 7 = 28
		
12.  Slope Problem: 
Given coordinates (x1 = 2, y1 = 4) and (x2 = 4, y2 = -1), find the
slope of the line.

Slope = (y2 ? y1)/(x2 ? x1) = (-5)/2 = - 2.5

	
13.  Factor:
x2 - x - 90 = 	(x ? 10)(x+9)

14.  Reduce to lowest terms:
 	(x-2)(x+2)/(x+5)(x-2) = (x+2)/(x+5)	

15.  Solve for x and y using the addition method:
2x  + 3y = -6
x - 3y = 6		

3x = 0; x = 0


16.  Solve for x and y using the substitution method:
-2x + y = 3
- x + y = 2	

y = 2 + x ; -2x + 2 + x = 2 ; -x = 0 ;

x = 0

17.  Simplify:
(10^-9)^1/3 = 

10^-9*1/3 = 10^-3  This can also be written as 1/10^3


18.  Solve for x:
(7x + 1)^1/2 = 6; 7x + 1 = 6^2

7x = 35; x = 5


19.  Solve for x:
x2 + 4x - 21 = 0   

(x + 7)(x ? 3) = 0

x = 3, -7


20.  Solve using the quadratic formula:
x2 + 12x - 45 = 0         

In an equation with the form ax^2 + bx + c = 0, we add (b/2a)^2 to
each side: the ultimate solution being:

X = [-b +- (b2 ? 4ac)^1/2]/2a ; x = [-12 +- (144 ? 4*(-45))^1/2]/2 =
[-12 +- (324)^1/2]/2 = [-12 +- 18]/2;

x = 6/2 = 3;
x = -30/2 = -15


21.  Solve for x:
x/90 = 2/30

x = (90 * 2)/30 = 6

22.  Solve for x:
x^2 = 144      

x^2 ? 144 = 0; (x ? 12) (x + 12) = 0 

x = -12, 12

23.  Change to logarithm form:
10^2 = 100     

Google has a calculation function that aids this simply by entering
log 100 in the Google search window:

log 100 = 2

2 = log (base 10) 100, which is commonly written 2 = log10 100

24.  Solve for x: e^x = 12        

e = 12 1/x ; if we use e as the natural log, 2.7183 we can solve for x;

2.7183 = natural ln 12 = 2.4849

Again, you can use the Google to figure the natural ln of 12 by typing
?ln 12? into the search window.

25.  Solve for x: 
10^x = 10,000    
   
10^1 = 10
10^2 = 100
10^3 = 1,000
10^4 = 10,000
10^100 = Googol

Obviously x = 4

Alternately you can take log (base10) of 10,000 = 4

If there are any questions or confusion over format, please let me know.

Google search strategy:
Natural logarithm e
Quadratic equation


Best regards,

Omnivorous-GA
liquideet-ga rated this answer:5 out of 5 stars
Great Answer! Great Explanation! Great Comments! A+

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