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Subject:
Mathematical Growth Forecast
Category: Science > Math Asked by: bostonman-ga List Price: $10.00 |
Posted:
02 Mar 2005 13:40 PST
Expires: 01 Apr 2005 13:40 PST Question ID: 483641 |
Hello, Looking for some help with predicting revenue growth for a company. Mainly I'd like a spreadsheet to show growth. We will be lauching products each month. Starting with 10 products. Each month we will launch 8 additional units. The units revenue growth is as follows: Month 1: $200 Month 2: $500 Month 3: $1000 Month 4: $2500 Month 5: $5000 Month 6: $5500 Month 7: $6500 Month 8: $7500 Month 9: $8500 Month 10: $9500 Month 11 $10500 Month 12 $11500 I need an equation and chart showing overall revenue by month taking the above growth rate. How much revenue would be generated each month for a year starting with 10 units in January and adding 8 units per month. Ie, at the end of the year there would be 98 units. I just need to show revenue by month on an excel spreadhseet and know the formula. Thanks! Mike | |
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Subject:
Re: Mathematical Growth Forecast
Answered By: elmarto-ga on 03 Mar 2005 05:46 PST |
Hi bostonman! You can download the Excel spreadsheet I made from the following link http://www.angelfire.com/alt/elmarto/googleanswers/483641Revenue.xls (Right-click on this link and choose Save Target As...) I've included the ability of changing the revenue growth per month, the number of initial products, and the number of products that are added per month. I think the spreadsheet is pretty self-explanatory, but if you don't understand how to make the changes you intend to, or if you feel something's missing from it, please don't hesitate to request clarification. Best wishes! elmarto | |
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Subject:
Re: Mathematical Growth Forecast
From: ticbol-ga on 03 Mar 2005 01:41 PST |
Here is one way. For the 1st month, Revenue = 10(200) = $2,000. For the 2nd month, Revenue = 10(500) +8(200) = $6,600. For the 3rd month, Revenue = 10(1000) +8(200+500) = $15,600. For the 4th month, Revenue = 10(2500) +8(200+500+1000) = $38,600. For the 5th month, Revenue = 10(5000) +8(200+500+1000+2500) = $83,600. For the 6th month, Revenue = 10(5500) +8(200+500+1000+2500+5000) = $128,600. For the 7th month, Revenue = 10(6500) +8(200+500+1000+2500+5000+5500) = $182,600. For the 8th month, Revenue = 10(7500) +8(200+500+1000+2500+5000+5500+6500) = $244,600. For the 9th month, Revenue = 10(8500) +8(200+500+1000+2500+5000+5500+6500+7500) = $314,600. For the 10th month, Revenue = 10(9500) +8(200+500+1000+2500+5000+5500+6500+7500+8500) = $392,600. For the 11th month, Revenue = 10(10500) +8(200+500+1000+2500+5000+5500+6500+7500+8500+9500) = $478,600. For the 12th month, Revenue = 10(11500) +8(200+500+1000+2500+5000+5500+6500+7500+8500+9500+10500) = $572,600. That is it. Can you graph that? The graph looks like the first-quadrant half of a vertical parabola that opens upward whose vertex is at (0,0). Like y = a(x^2), where x is for months and y is for revenues. ------------ I know, I know. You are asking for spreadsheet formulas. But that is too complicated for me. Too many inputs. I am used to finding easier/faster solutions to problems---rules or no rules. There must many ways to solve a problem. Why stick to one? Like the one above. Is it not easier to just copy that for a previous month, paste it below, and then just change some inputs to get that for the next month? Besides, I am not an expert on doing spreadsheets. This is just a comment, so.... |
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