Using an intergration of six numbers for a combined total of 150 how
many combinations are there using the numbers from one to forty five,
bearing in mind no numbers can repeat themselves in the one
intergration of six numbers.

---

Request for Question Clarification by mathtalk-ga on 10 Mar 2005 07:20 PST

Hi, trebla-ga:

The technical name for such things (assuming that by "an integration"
you simply mean "a sum"), is a partition (although this word can mean
other things, in other mathematical contexts).

At any rate, it's important to state whether the order of the summands
"matters".  In other words when counting the number of different
partitions, would you consider these possibilities to be the same or
different:

  5 + 10 + 20 + 30 + 40 + 45 = 150 = 45 + 40 + 30 + 20 + 10 + 5

If the order of summands matters, we call the possibilities ordered
partitions; otherwise we would say (when order does not matter) that
they are unordered partitions.

regards, mathtalk-ga

---

Clarification of Question by trebla-ga on 10 Mar 2005 22:19 PST

Re: Mathtalk-ga

I mean unordered partitions.

by "integration" do you mean addition; as in
43+44+45+5+6+7

... and do you mean integers?

Best

This might be helpful:

http://answers.google.com/answers/threadview?id=377517

you mean like the lottery except that a number cannot repeat itself? 
try: 10 x 9 x 8 x 7 x 6 x 5