Write a net ionic equation for the mixing of aqueous lead (II) nitrate
with lithium iodide.

Hi anais35!!


Aqueous lead (II) nitrate reacts with aqueous lithium iodide to
produce solid lead (II) iodide and aqueous lithium nitrate:

1)The balanced molecular equation:

Pb(NO3)_2 (aq) + 2LiI (aq) ---> PbI2 (s) + 2LiNO3 (aq)
                                   

2)The full ionic equation:

 (+2)        (-)        (+)       (-)                     (+)         (-)
Pb (aq) + 2NO3 (aq) + 2Li (aq) + 2I (aq) --> PbI2 (s) + 2Li (aq) + 2NO3 (aq)
  

3)The net ionic equation:

To get the net ionic equation the spectator ions (ions that do not
participate in the reaction) must be removed from the full ionic
equation.
Then we have for this reaction:

 (+2)      (-)
Pb (aq) + 2I (aq) ---> PbI2 (s)


4)The interpretation:

Lead and iodide ions react to produce insoluble (solid) lead iodide.

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I hope that this helps you. Feel free torequest for a clarification if you need it.

Regards.
livioflores-ga