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| Subject:
Statistics -
Category: Miscellaneous Asked by: wrench234-ga List Price: $70.00 |
Posted:
23 Mar 2005 12:43 PST
Expires: 22 Apr 2005 13:43 PDT Question ID: 499312 |
Studying for the GMAT and statistic is hard. Please provide formula as well.
Is the educational achievement level of students related to how much
the state in which they reside spends on education? In many
communities this important question is being asked by taxpayers who
are being asked by their school districts to increase the amount of
tax revenue spent on education. In this case, you will be asked to
analyze data on state spending and achievement scores in order to
determine whether there is any relationship between government
spending and student achievement in the public schools.
The federal government?s National Assessment of Educational Progress
(NAEP) program is frequently used to measure the educational
achievement of students.
Student Spending Achievement Data and Worksheet 1 shows the total
current spending per pupil per year, and the composite NAEP test score
for 35 states that participated in the NAEP program. The composite
score is the sum of the math, science, and reading scores on the 1996
(1994 for reading) NAEP test. Pupils tested are in grade 8, except for
reading, which is given to fourth-graders only. The maximum possible
score is 1300.
Student Spending Achievement Data and Worksheet 2
shows the spending per pupil for 13 states that did not participate in
relevant NAEP surveys.
a. Develop numerical and graphical summaries of the data.
b. Use regression analysis to investigate the relationship
between the amount spent per pupil and the composite score on the NAEP
test.
c. Do you think that the estimated regression equation developed
for these data could be used to estimate the composite scores for the
states that did not participate in the NAEP program?
d. Suppose that you only considered states that spend at least
$4000 per pupil but not more than $6000 per pupil. For these states,
does the relationship between the two variables appear to be any
different than for the complete data set? Discuss the results of your
findings and whether you think deleting states with spending less than
$4000 per year and more than $6000 per pupil is appropriate.
e. Develop estimates of the composite scores for the states that
did not participate in the NAEP program.
f. Based upon your analyses, do you think that the educational
achievement level of students is related to how much the state spends
on education?
National Assessment of Educational Progress (NAEP) data
State Spending and Student Achievement Scores
for the 35 states that participated
State Spending
per Pupil Composite
Score
1 Alabama 3,77 604
2 Arizona 4,04 618
3 Arkansas 4,060 615
4 California 4,917 580
5 Colorado 4,772 644
6 Connecticut 7,629 657
7 Delaware 6,208 615
8 Florida 4,934 611
9 Georgia 4,663 611
10 Hawaii 5,532 580
11 Indiana 5,128 649
12 Iowa 5,060 665
13 Kentucky 5,020 626
14 Louisiana 4,049 581
15 Maine 5,561 675
16 Maryland 6,100 625
17 Massachusetts 6,413 658
18 Minnesota 5,477 661
19 Mississippi 3,423 582
20 Missouri 4,483 641
21 Montana 4,985 667
22 Nebraska 5,410 660
23 New Mexico 4,097 614
24 New York 8,162 628
25 North Carolina 4,521 629
26 North Dakota 4,374 671
27 Rhode Island 6,554 638
28 South Carolina 4,304 603
29 Tennessee 3,800 618
30 Texas 4,520 627
31 Utah 3,280 650
32 Washington 5,338 639
33 West Virginia 5,247 625
34 Wisconsin 6,055 667
35 Wyoming 5,515 657
State Spending (per student) for the 13 states
that did not participate in the NAEP study
State Spending
per Pupil ($)
1 Alaska 7890
2 Idaho 3602
3 Illinois 5297
4 Kansas 5164
5 Michigan 6391
6 Nevada 4658
7 New Hampshire 5387
8 Ohio 5438
9 Oklahoma 4265
10 Oregon 5588
11 Pennsylvania 6579
12 South Carolina 4067
13 Vermont 6269
There were two states that no data was reported
South Dakota
New Jersey |
|
| Subject:
Re: Statistics -
Answered By: leapinglizard-ga on 24 Mar 2005 16:00 PST Rated: ![]() |
Dear wrench234, I have worked out the exercise below. If you feel that any part of my answer requires correction or elaboration, please let me know by posting a Clarification Request so that I may fully meet your needs before you assign a rating. Regards, leapinglizard a. Let us first consider the spending and testing data for states that participated in the NAEP program. The spending per pupil ranges from a minimum of $3280 to a maximum of $8162. The median is $4985, which means that half the states spent no more than this value and half the states spent no less. We can compute the median by sorting the 35 values and picking the 18th one, which leaves an equal number of values, namely 17, to the left and to the right. The mean spending is $5068.60, which we calculate by summing the values and dividing by 35. David M. Lane: HyperStat: Median http://davidmlane.com/hyperstat/A27533.html David M. Lane: HyperStat: Mean http://davidmlane.com/hyperstat/A15885.html The test scores range from a minimum of 580 to a maximum of 675. Their median is 628 and the mean is 631.17. Since we have a pair of values for each state in the NAEP program, we can plot them graphically as follows. 680 | X | X 670 | X X | X 660 | XXX X X | 650 | X X | X 640 | X X | X 630 | | X X X 620 | X X | X X 610 | X X | X X 600 | X X | 590 | | 580 | X X X X | +---------+---------+---------+---------+---------+---------+------ 3200 4000 4800 5600 6400 7200 8000 We only have a single value for each state that did not participate in the NAEP program, so we cannot plot points for this data set. However, we can still characterize it numerically using the same measures. The spending per pupil in states that did not participate in the NAEP program ranges from a minimum of $3602 to a maximum of $7890. The median is $5387, and the mean is $5430.38. b. We shall perform a least-squares linear regression on the first data set. This entails computing the equation of the line such that the sum of the squares of the vertical distance from each point to the line is minimized. If we have n points for which we wish to construct a line with equation y = a + bx, the values of a and b are given by the following formula. sum(y)*sum(x^2) - sum(x)*sum(x*y) a = --------------------------------- n*sum(x^2) - sum(x)^2 n*sum(x*y) - sum(x)*sum(y) b = -------------------------- n*sum(x^2) - sum(x)^2 Engineering Fundamentals: The Least-Squares Line http://www.efunda.com/math/leastsquares/lstsqr1dcurve.cfm In our case, we already know that n = 35. To compute a and b, we shall furthermore have to know sum(x), sum(y), sum(x^2), and sum(x*y). Our x values are the spending per pupil, while the y values are the test scores. sum(x) = 177401 sum(y) = 22091 sum(x^2) = 939271579 sum(x*y) = 112317357 We can now calculate a and b as follows. 22091*939271579 - 177401*112317357 a = ---------------------------------- = 587.32 35*939271579 - 177401*177401 35*112317357 - 177401*22091 b = ----------------------------- = 0.00865 35*939271579 - 177401*177401 So the equation of the line that minimizes the sum of the squares of the vertical distance from each point is the following. y = 587.32 + 0.00865x c. The equation arrived at by least-squares linear regression over the entire population of the NAEP data does not provide a good basis for estimating composite scores for other states. This is because visual inspection of the plotted data shows the great majority of points clustered around a line with a distinctly positive slope, yet the regression equation results in a nearly flat line. This means that the regression has been distorted by the outliers, which are the few data points lying far from the line. d. After removing from consideration those states where the average spending per pupil exceeds $6000 or falls below $4000, we end up with 24 points. In this data set, the spending per pupil ranges from a minimum of $4040 to a maximum of $5561, with a median of $4934 and a mean of $4833.63. The test scores range from a minimum of 580 to a maximum of 675, with a median of 629 and a mean of 631.21. To carry out a least-squares linear regression, we recompute the pertinent values. sum(x) = 116007 sum(y) = 15149 sum(x^2) = 566829691 sum(x*y) = 73359391 15149*566829691 - 116007*73359391 a = --------------------------------- = 524.31 24*566829691 - 116007*116007 24*73359391 - 116007*15149 b = ---------------------------- = 0.0221 24*566829691 - 116007*116007 We now have a line whose equation is the following. y = 524.31 + 0.0221x The y-intercept of this line is similar to that obtained over the entire population. Its slope is also slightly positive, but more pronounced than that of the earlier one. Overall, we conclude that the relationship between the variables is similar in this reduced data set. Although the new linear regression is not applicable to the entire population, it is reasonable to consider the reduced set because it eliminates some obvious outliers. In other words, it is helpful to consider the trend as it applies to states nearer the middle ground rather than those with extremely small or extremely large educational budgets. Rather than arbitrarily cutting off the range at $4000 and $6000, however, it would be even more statistically meaningful if we restricted consideration to those states whose budget lies within one or two standard deviations of the mean. e. Using the least-squares fit obtained by the second linear regression above, we proceed as follows. For each state in the non-participant data set, we take the state spending per pupil as the x value and apply the line equation to find the y value, which is our estimate of the test score that would be obtained by that state. Alaska: 524.31 + 0.0221*7890 = 698.80 Idaho: 524.31 + 0.0221*3602 = 603.97 Illinois: 524.31 + 0.0221*5297 = 641.46 Kansas: 524.31 + 0.0221*5164 = 638.51 Michigan: 524.31 + 0.0221*6391 = 665.65 Nevada: 524.31 + 0.0221*4658 = 627.32 New Hampshire: 524.31 + 0.0221*5387 = 643.45 Ohio: 524.31 + 0.0221*5438 = 644.57 Oklahoma: 524.31 + 0.0221*4265 = 618.63 Oregon: 524.31 + 0.0221*5588 = 647.89 Pennsylvania: 524.31 + 0.0221*6579 = 669.81 South Carolina: 524.31 + 0.0221*4067 = 614.25 Vermont: 524.31 + 0.0221*6269 = 662.95 f. It is evident from the linear regressions on both the entire population and the reduced data set that there is a mild positive relationship between state spending per pupil and average achievement on the NAEP test. From the second linear regression, we conclude that for every 1000 dollars spent per pupil, the average test score rises by about 20 points. We believe that more statistical analysis is warranted to develop more precise measures of the correlation between educational spending and educational achievement. |
wrench234-ga
rated this answer:
accpeted please post for the credit |
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