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Subject:
Math
Category: Science > Math Asked by: mike1269-ga List Price: $20.00 |
Posted:
23 Mar 2005 16:44 PST
Expires: 22 Apr 2005 17:44 PDT Question ID: 499428 |
What is the negative compound annual growth rate for a starting point of 12,022 and an ending point of -613 if there are 104 compounding periods and how do you calculate it? The formula: (Futureval/Presentval)^(1/Periods)-1 doesn't yield an answer. The series is a straight regression line, actually, and the equation is y= -121.487x+12022.045. Also, is there a general relationship between the slope of the line and the compound growth rate? | |
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There is no answer at this time. |
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Subject:
Re: Math
From: reinedd-ga on 23 Mar 2005 19:49 PST |
If you talk about a negative compound annual growth rate you're telling me that, every period,you need to take of a <<<constant percentage>>>> of last period price to get today price price today = last period price x (1+decrease) or price today = original price x (1+decrease)^(number of period) this is a exponential you cannot get the "decrease" number with a regression, you need to use a exponential fit ( y=a*e^(bx) ) in this case "decrease" = e^b-1 Now if you want to take a <<<<<<<constant amount>>>>>>> out of last period price you get price today = last period price + decrease or price today = original price + decrease x number of period there you have your regression y= 12022.045-121.487x original price = 12022.045 and the decrease (slope) =-121.487 |
Subject:
Re: Math
From: scanp-ga on 06 Apr 2005 13:05 PDT |
The equation y = -121.487n + 12022.045 gives the average annual aluminium price in period n. For example in period 104, the equation gives a value of -612.6 which is an approximation for the price in period 104 (2004). In order to get a relation between the compound annual growth rate and the slope of the line, a simple way will be to equate the two relations. That is price in any period n can also be given by the relation y = 12022*(1+r)^n where r is the annual growth rate and n is the period. However as mentioned in other comments this will work only is y is positive. In such a scenario when y is positive, we get 12022*(1+r)^n = -121.487n + 12022.045. For any given n we can get a value of r as long as the price is positive. In its general form, the equation can be written as a(1+r)^n = mn + b where a is the starting value, r is the annual compounding rate, n is the period, m is the slope of the regression line and b is the intercept. For small r (<<1), we can use the approximation (1+r)^n = 1+rn to solve for r. r = (mn+b-1)/n. However, this will work only if y is positive. And this too will only be an approximation for r in any given period. The highest n that keeps y positive is 98 and using that to solve for r, we get an annual growth rate of -4.62%. As is obvious, this excludes the last 6 periods. |
Subject:
Re: Math
From: scanp-ga on 06 Apr 2005 13:13 PDT |
A minor correction in the relation between slope and annual growth rate r r = ([(mn+b)/a]-1)/n. |
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