Google Answers Logo
View Question
 
Q: binding assay ( Answered,   0 Comments )
Question  
Subject: binding assay
Category: Miscellaneous
Asked by: val1-ga
List Price: $10.00
Posted: 03 Apr 2005 10:01 PDT
Expires: 03 May 2005 10:01 PDT
Question ID: 504352
100fmoles of insulin receptors displayed by 1 million beta cells in
binding assay. How do you calculate the number of receptors on 1 cell?
Answer  
Subject: Re: binding assay
Answered By: welte-ga on 03 Apr 2005 12:55 PDT
 
Dear Val,

Thanks for your question.  A mole is an Avagadro's number of
particles.  Avagadro's number is 6.02x10^23.  The significance of this
number is that for this number of particles of any homogeneous
substance (atoms, molecules), the weight in grams will equal the
substance's atomic weight in Daltons.  An example: If you have
6.02x10^23 hydrogen atoms, each of which has a mass of 1 Dalton, then
the mass of this large number of hydrogen atoms is 1 gram.

Now to your question.  100 fmoles is 100 femtomoles of insulin
receptors.  You don't need to know the mass of the insulin receptors
to solve the problem.

100 femtomoles = 100 x (10^-15) moles   [femto means 10^-15]

So, we have 100 x 10^-15 moles of insulin receptors on 10^6 beta cells.

If we assume that the receptors are distributed evenly (a big
assumption in vivo), then we have
100 x 10^-15 x 6.02 x 10^23 receptors / 10^6 beta cells = 6.02 x 10^4
receptors / cell = 60,200 receptors / cell.

Final answer: 60,200 receptors / cell


Here's a page on moles and Avogadro's number for more details:

http://en.wikipedia.org/wiki/Mole_%28unit%29

If you're interested, here is a page on Avogadro himself:
http://en.wikipedia.org/wiki/Avogadro


I hope this information was helpful.  Feel free to ask for clarification.

         -welte-ga
Comments  
There are no comments at this time.

Important Disclaimer: Answers and comments provided on Google Answers are general information, and are not intended to substitute for informed professional medical, psychiatric, psychological, tax, legal, investment, accounting, or other professional advice. Google does not endorse, and expressly disclaims liability for any product, manufacturer, distributor, service or service provider mentioned or any opinion expressed in answers or comments. Please read carefully the Google Answers Terms of Service.

If you feel that you have found inappropriate content, please let us know by emailing us at answers-support@google.com with the question ID listed above. Thank you.
Search Google Answers for
Google Answers  


Google Home - Answers FAQ - Terms of Service - Privacy Policy