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Subject:
Wire Stiffness vs. Crossectional Area
Category: Science > Physics Asked by: bingalls-ga List Price: $5.00 |
Posted:
07 Apr 2005 06:42 PDT
Expires: 07 May 2005 06:42 PDT Question ID: 506249 |
How do I calculate how much the relitive stiffness or bend resistance of a wire, of the same material (say copper), goes up as the wire gauge increases? From say 22AWG to 20AWG, as an example. |
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Subject:
Re: Wire Stiffness vs. Crossectional Area
Answered By: hedgie-ga on 07 Apr 2005 11:29 PDT Rated: |
Stiffnes of the circular beam increases is 4th power of diameter, so, if you want, as square of crossection area. For general crossesction it depends (by coincidence) on the moment of inertia of the crosssection, as shown here: http://pergatory.mit.edu/2.007/Resources/calculations/bending/bending.html The complete expression for deflection : ----------------------------------------- We will consider only the simplest, a rectangular beam of width b , height 2c and length between supports L, with a single concentrated load W at the centre The deflection at the centre of the beam is ? = WL3/48IY. We have made a lot of assumptions, but the result agrees well with practice. For beams of other shapes, the results are the same if the proper moment of inertia of area is used. where I is the moment of inertia of area about the neutral axis, where Y = (3? + 2?)?/(? + ?) is called Young's Modulus. A more common symbol for it is E. Details and picture: http://www.du.edu/~jcalvert/tech/elastic.htm |
bingalls-ga
rated this answer:
Simple, concise answer. The link with a spreadsheet was a plus. |
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Subject:
Re: Wire Stiffness vs. Crossectional Area
From: namcaps-ga on 07 Apr 2005 11:40 PDT |
Simple answer: Yes, an object's resistance to bending is proportional to the moment of inertia along the neuteral axis. With a bit of simplification, the moment of inertia for an object with a circular cross section (wire for example) is proportional to the radius^4, or the area-squared. |
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