![]() |
|
![]() | ||
|
Subject:
meeting travel cost analysis
Category: Miscellaneous Asked by: brianj-ga List Price: $5.00 |
Posted:
05 Aug 2002 13:51 PDT
Expires: 04 Sep 2002 13:51 PDT Question ID: 50917 |
How do I find the least cost location for a meeting with participants coming from different locations | |
| |
| |
| |
| |
| |
|
![]() | ||
|
Subject:
Re: meeting travel cost analysis
Answered By: websearcher-ga on 06 Aug 2002 09:13 PDT Rated: ![]() |
Hi brianj-ga: We've finished the first part of solving your travel problem: clarifying exactly what the parameters are that need to be included in our calculations. Given your comments, it appear that the only things you need to take into account are: 1. Lodging expenses for each attendee, except if they are within 20 miles of the meeting place. 2. Air travel expenses for each attendee, except if they are within 100 miles of the meeting place. Everything else is either being ignored or is being assumed to be equal cost for all locations, so does not need to be included in your "least cost location" calculations. The next thing you need to do is determine, for each attendee, whether they are within the 100-mile radius of a city with regular air service. (You can assume that the meeting itself will be held in a city with regular air service.) Create a table that has the attendee name in one column and a list of 100-mile radius cities for each in the second column. Create a third column in that table for the 20-mile radius cities for each attendee. (The cities in column 3 will be a subset of the cities in column 2.) Unless your attendees all live in the boonies (i.e., not near a city with air service) or they are extremely far-flung from each other individually, there's a very good chance that your least cost location is going to be listed in column 2 (and probably column 3). Make a separate list of the cities in all of column 2, ordered by decreasing order of the number of times the city name appears in column 2. (So, the city appearing most often would go at the top of the list.) Now you start getting into gathering of data that is a little more work-intensive - air travel expenses. I can't really advise you too closely on *how* to collect this data, since I don't know whether your company prefers a particular carrier or uses a particular travel agency or uses online ticket booking sites. However you do go about gathering the information, do the following: * For each city in your ordered list of cities created above, find the cost of air travel for each attendee from their home city to there. This, of course, will vary depending on time of year, length of stay, days of travel, coach/business class, etc. * For each city in your ordered list of cities created above, perform the following calculation: location cost = sum of all airfares needed (for those not within 100 miles) + (number of nights * number of attendees needing lodging * lodging per diem) Once you have gone through all the cities on your ordered list, choose the city with the lowest location cost. We'll call that the "first candidate". As I said above, there's a good chance this first candidate is going to be the lowest cost location, especially if a decent proportion of your attendees can save flight/lodging costs because it's close to home. However, if your attendees are widespread, then a more "central" location might have a lower cost. A good way to find what "central" location might be cheapest is to consider *major hub* airport centers where many transfers on non-direct flights take place. Some of these in the US include Chicago, Dallas, Memphis, and other midwestern cities. A good way to determine which of these centers might be worth investigating is to look at the flights found in the earlier part of this process and see which, if any, of these hubs were frequently listed as transfer points in those flights. For each of these "hub" cities, the calculation is similar: location cost = sum of all airfares needed + (number of nights * number of attendees * lodging per diem) Even though all attendees need lodging, we must retain the lodging cost in our calculations to insure that the location costs can be compared to the earlier ones. If any of these "hub" cities has a location cost lower than the current first candidate city, then make the lowest cost city among them the new "first candidate". The last thing you might want to do is consider other "central" cities that might not be major hubs. I suggest taking a map of the US and putting pins in for each attendee, Then, see if any large cities (that don't have a pin in them and aren't major hubs you've already checked out) are near the geographic center of all those pins. For each such city, the formula is the same as above: location cost = sum of all airfares needed + (number of nights * number of attendees * lodging per diem) Again, if any of these "geographic center" cities has a location cost lower than the current first candidate city, then make the lowest cost city among them the new "first candidate". At this point you are done. Go with the current first candidate, your lowest location cost. As for how to perform the various calculations presented here, you could do them on paper, with a spreadsheet, or however is most convenient for you. Please, if you need any clarification before you rate this answer, please ask - I'm only too happy to help. Happy travels! websearcher-ga | |
|
brianj-ga
rated this answer:![]() Very good answer. It helps a lot in working through the problem and can be used repeatedly in the future. Thanks. |
![]() | ||
|
Subject:
Re: meeting travel cost analysis
From: websearcher-ga on 05 Aug 2002 14:06 PDT |
Hi brianj: The short answer to this short question is that it's not as simple as it might seem. There are an extra-ordinary number of variables involved. I have dinner guests coming in a few minutes, but if no-one else comes up with a concise answer in the next couple of hours, I'll try writing an "algorithm" for how you might go about forming the question, making appropriate decisions, and calculating the cheapest option. websearcher-ga |
Subject:
Re: meeting travel cost analysis
From: curepi-ga on 05 Aug 2002 14:22 PDT |
Hi Brian : Before websearcher-ga comes with an well thought algorithm ( which would be my approach if you would have posted your question in the computer/software section ), please clarify if you are looking for 1. a one time solution for a specific problem 2. a repeatable solution (e.g. computer program ) If option 1 is the case, you would need to specify, at least, where the participants are coming from ( search is different if participants come from all over Germany into Munich than from all over the world into the States.) I'm not telling the answer is different, but the search is different. Also some criteria for the "least cost" issue would be needed : transport cost only participants travel time also a cost ( all the same, or different hourly rates) A little clarification would help, specially before websearcher-ga and his dinner guests finish their coffee. Good luck, Curepi |
Subject:
Re: meeting travel cost analysis
From: leeann-ga on 05 Aug 2002 14:22 PDT |
I have found that the cheapest way to have a meeting / conference with people from everywhere is to do an online conference with an online conference center like WebEx (www.webex.com) or PlaceWare (www.placeware.com). How it works is the online conference center has deals from one time meetings to "renting" space for a year. Each person logs onto the website and is connected "live time" with the other participants (or if you choose, you can be the omnipotent presenter and they can merely watch) via the website as well as a telephone conference. You can show live powerpoint presentation, use white boards, live polling, and many other things. The web conferencing vendor also provides all of the technical support you will need. When you take hotel and airfare into consideration, not to mention catering and event staff, the breakdown per person is quite cheap. To get a better idea of how it works, check out their websites and take the tours. As far as pricing ballpark goes, lets say you have 10 people who need to meet about once a month, all from different places, PlaceWare will rent you online space at $750 a month. If you are still not convinced, most vendors will let you participate in an online demonstration for free. |
Subject:
Re: meeting travel cost analysis
From: brad-ga on 05 Aug 2002 15:11 PDT |
Hi Brianj: I did this often before I retired. We had offices and personnel all over the country. It's not very complex and I did use a simple spreadsheet. For each person you would need variables like airfare and hotel expenses. I usually had a choice of 4 or 5 cities for the meetings. There are many reasonable approaches, but I'd break the people by their office(or their local airport) as columns in the spreadsheet. The rows would consist of the destination cities. For each Office, there would be a few columns per person consisting of airfare, meals,lodging,incidentals(taxi,parking fees). These 4 columns per person would have data that depended on the Destination City row. That meant that if the gathering was in a city where 5 employees resided, those employees would show nothing for airfare, per diem, incidentals as they were not on travel status, but local folk. As soon as all the data was input, you just summed across the City Destination Row to get the total expense for each Destination City. It can also be done the other way, using the Destination City as the column. In may case, the spreadsheet was presented to management for decisionmaking since intangibles exist which can't be handily placed on the spreadsheet. Intangibles such as a meeting in Jacksonville, Florida might be $1000 cheaper than one in Orlando, but afterhours Orlando might be much more enjoyable for the people attending. As far as data gathering, the secretaries in each office would gather the relevant information for their people and email it to me for inclusion in a spreadsheet. Brad-ga |
If you feel that you have found inappropriate content, please let us know by emailing us at answers-support@google.com with the question ID listed above. Thank you. |
Search Google Answers for |
Google Home - Answers FAQ - Terms of Service - Privacy Policy |