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Subject:
Physics of a Subway Train
Category: Science > Physics Asked by: x911gt2-ga List Price: $20.00 |
Posted:
26 Apr 2005 20:08 PDT
Expires: 04 May 2005 12:51 PDT Question ID: 514723 |
I am working on a computer program that determines the minimum time it will take for a subway train to go from one station to the next based on a few parameters: The parameters to the problem are all positive integers not greater than 1000. * d - the distance between stations, in metres * m - the maximum allowable speed of the train, in metres/sec * a - the maximum absolute acceleration of the train, in metres/sec2 * j - the maximum absolute jerk, in metres/sec3 The train must be completely stopped at each station and must move in one direction at speeds not exceeding m. Acceleration can be positive (forward) or negative (backwards) but its absolute value must not exceed a. The last parameter, jerk, is the rate of change of acceleration in either direction. That is, acceleration cannot increase or decrease at greater than this rate. This parameter prevents toppling the standing passengers. For example, if the inputs are: d = 1000 m = 70 a = 20 j = 1 The correct answer to 3 sig figs is 31.7 I have gotten close to this, but I am missing something. Basically, I am looking for the math to figure out the problem. Thanks in advance. | |
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There is no answer at this time. |
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Subject:
Re: Physics of a Subway Train
From: xarqi-ga on 26 Apr 2005 21:15 PDT |
I'm sorry, I can't help you with this interesting problem, but I have one comment: That's some subway train you've got there! 70 m/s top speed = about 160,000 miles an hour! I hope you're using maglev and running in an evacuated tunnel. (And don't expect me to shovel the coal!) A guess that makes j=2 now if you count me. :-) |
Subject:
Re: Physics of a Subway Train
From: x911gt2-ga on 27 Apr 2005 00:00 PDT |
Actually, 70 m/s = ~156mph... Easy mistake to make :-) Google calculator works wonders... ://www.google.com/search?q=70+m%2Fs+to+mph Thanks though! |
Subject:
Re: Physics of a Subway Train
From: xarqi-ga on 27 Apr 2005 01:07 PDT |
D'oh! Make that j=3. I hope you have success. |
Subject:
Re: Physics of a Subway Train
From: iang-ga on 27 Apr 2005 05:31 PDT |
I agree with hedgie, in which case you can use the equations of motion. Where did 31.7 seconds come from? It seems too long, unless it's a round trip. Ian G. |
Subject:
Re: Physics of a Subway Train
From: philnj-ga on 27 Apr 2005 13:27 PDT |
This is an interesting diversion from what I am being paid to do! I don't have a total solution, but I think I know what the issues are. First, it is a third order polynomial in time because of the change in the acceleration. I don't yet know if you are required to solve this polynomial for time. Second, the parameters are limits, so you have to check that you don't exceed your limits in any step of the calculation. For example, it you accelerate at your limit, your final "Cruising speed" may be greater than your limit. Third, there are some assumptions you must make to solve for the initial conditions. One, you have to assume that the change in acceleration is the same in every instance. Second, you have to assume that the time of acceleration and deceleration is the same. I started with a simple graph of acceleration. It starts at zero, ramps up (at a rate j) to a steady value not to exceed a. It then ramps down at the same rate to a value of zero. I also split the problem in two halves. If you calculate the time it takes to get half way, you can forget about the second half of the acceleration graph that is the same as the first part but has negative values. Is this correct? I broke the graph into pieces timewise. By taking the integral of the acceleration curve, you get the velocity curve. Take the integral of the velocity curve and you have the distance curve. You know the distance, so all you have to do is solve for time. Easier said than done? Maybe I'll think about this overnight. |
Subject:
Re: Physics of a Subway Train
From: philnj-ga on 28 Apr 2005 06:29 PDT |
OK. I slept on it. The polynomial algebra gets a little scary, but the problem boils down to a couple concepts. First, there are four variables. 1. The rate at which the acceleration changes (j' limited by the input parameter j). 2. The length of time spent increasing your acceleration (time interval t0 to t1) 3. The length of time spent at a constant acceleration (time interval t1 to t2). 4. The time at which you reach constant cruising speed (time interval t2 to t4). BTW, you assume that you lower your acceleration at the same rate that you raise you acceleration (t3=t2+t1). You also divide the problem in half. If you know how long it takes to get half way there, you double it to get to your destination. If you think about it, these are the choices a train driver would make if his hand were on the throttle. Second concept: You have four variables and a set of given limits. And you are asked to find the MINIMUM time to get between two stations. That means maximizing acceleration without overshooting your destination. If you slog through the math, you can integrate the acceleration equations for the velocity and integrate velocity to get position. Position, velocity and acceleration are all subject to limits. That is as far as I've gotten so far. Is any of this helping, or am I talking to myself? Regardless, I'm enjoying this challenge. |
Subject:
Re: Physics of a Subway Train
From: x911gt2-ga on 28 Apr 2005 08:04 PDT |
Your concepts are correct. However, my problem is I am stuck with the math. |
Subject:
Re: Physics of a Subway Train
From: philnj-ga on 28 Apr 2005 08:19 PDT |
Be more specific. Are you having trouble modeling the problem or solving for the answer? I've got the model, but am having trouble working toward the solution. If you need what I can do, I'll be glad to cover it in more detail. I'm currently working on how to deal with the limits. I'm thinking that it is best to increase your acceleration as rapidly as possible and reach your speed limit if you can. But at each step, you have to check that you have not exceeded your limits. There are three cases. 1. You spend all your time increasing your acceleration and decreasing your acceleration. There is not enough distance or your maximum velocity is too low to get to your acceleration limit. 2. You can reach your acceleration limit, but there is not enough distance to level off at a cruising speed. 3. You can get to your max velocity and must stay at that speed until you have reach the half way point. I wish I could draw you about a half-dozen pictures. But I have no place to post them. |
Subject:
Re: Physics of a Subway Train
From: philnj-ga on 28 Apr 2005 09:50 PDT |
Wow, usually researchers are a model of decorum. But looks like this one is pissed at something. It is a physics problem, dude. No reason to criticize someone like that. The explanation of the maximum principle looks like what we are after. And the value we are calling jerk is simply the slope of the acceleration curve. It integrates to a third order time term. What it is or what causes it has no bearing on the solution. I think it was thrown in to make the problem more interesting (difficult). It worked. |
Subject:
Re: Physics of a Subway Train
From: x911gt2-ga on 28 Apr 2005 12:19 PDT |
philnj -- i appreciate all of your help. I have the model, but I am running into the same issues you are -- arriving at a solution. I've contacted a few of my professors, but they were unable to help me as well. What you were saying about increasing the acceleration as quickly as possible. Unfortunately, you can only increase the acceleration by the jerk rate, which for their example was 1m/s. I actually read that *most* trains stay in the 2/ms jerk rate range as a general principle. hedgie -- first off, i found out what jerk is...its you. I came to this place looking for help, not a lecture or for someone who would try and insult my intelligence. I am not a physics major, I am a programmer, so the physics part of this is all new to me. I don't need to switch schools, but I do recommend you take a course on how to interact with people in an acceptable manner. You were right about one thing. This is a homework assignment. However, my professor was clear in stating that we can use any availble resources to solve our problem. I am not asking you or anyone else to write the program. I just wanted help in figuring out the physics of the problem. The assignment for me is programming, not physics. Anyways, you did succeed in leaving a negative impression of what google researchers are supposed to be. Maybe they should do a better job of screening. As for your peace offerings, I don't need them. |
Subject:
Re: Physics of a Subway Train
From: hedgie-ga on 28 Apr 2005 20:00 PDT |
I am sorry of I insulted your intelligence, when I just to provoke it to some activity. If you would care to use it, you could actually see that Portjagin principle provides an algorithm: a/j is time to reach max a a/v " max v d/v " coasting 'remaining' distance then you repeat that backwards, add the times and you are home, I eman at the next station but of course - you do not need that so sorry again. You do not have to change schools, It just meant that that you do not need to all accept statement posted on the web without some critical evaluation .. |
Subject:
Re: Physics of a Subway Train
From: hedgie-ga on 29 Apr 2005 01:56 PDT |
I also apologize for some missing words in my msg: "..It just meant that that you do not need to all ..." should have been: ".. It just meant that that you do not need to ACCEPT all .." (may be I should wake up first, next time, before responding). and perhaps you can try to look at it from the other side: What should a researcher do, when s/he tells customer that his assumption is incorrect, and customer just keeps repeating it, without any intelligent argument to support his assertion? An URL to some web-page is not an argument, since web is full of nonsense particularly when it comes to physics. |
Subject:
Re: Physics of a Subway Train
From: x911gt2-ga on 29 Apr 2005 03:04 PDT |
Are you seriously still ranting about this? You state that you repeadetly told me that my assumption was wrong. However, this was not an assumption. Jerk, which is the rate at which acceleration changes (im sure you already knew that), is what causes toppling, whiplash and so forth. That is why when engineers build rollercoasters and subways, they take jerk into account. Just because you are a 'researcher' doesn't mean you are always right. I even asked my physics professor, who used to work as a roller coaster engineer to give me an explanation. Here it is: "Jerk is important when evaluating the destructive effect of motion on a mechanism or the discomfort caused to passengers in a vehicle. The movement of delicate instruments needs to be kept within specified limits of jerk as well as acceleration to avoid damage. When designing a train the engineers will typically be required to keep the jerk less than 2 metres per second cubed for passenger comfort." -- Phil Gibbs Also, check out wikipedia, which gives a good explanation: http://en.wikipedia.org/wiki/Jerk "Jerk is used at times in engineering, especially when building roller coasters. Some precision or fragile objects?such as passengers, who need time to sense stress changes and adjust their muscle tension, or suffer e.g. whiplash..." It's pretty obvious that jerk does come into play in this problem. Yes, acceleration can make someone fall if it becomes too great...but on a smaller scale, the rate at which it changes (JERK) can have the same effect. In the case of this problem, this is the situation. Is that intelligent enough for you? I am not claiming to be an expert on physics, but I did do my research on this problem. I went as far as I could and that is why I came here for assistance. The first URL I gave you was to the problem. That way you could see what I was talking about. I wasn't saying you were wrong. But now I am. So am I going to look at it from your side? No. Why? Primarily, because I am offering YOU, the researcher, MONEY to help with my problem. When it comes down to it, the customer is always right (in a sense). You seriously should think about how you approach people from now on. I noticed you deleted your rude posts -- good move to cover yourself. I hope you mend your ways and become a bit more open minded. Good luck. |
Subject:
Re: Physics of a Subway Train
From: hedgie-ga on 29 Apr 2005 05:30 PDT |
x911: Are you seriously still ranting about this? H: No. Not seriously. x911: I am offering YOU, the researcher, MONEY H: When researcher switches from RFC (on top) to comments (on the bottom) s/he does not work for money. Standards are more relaxed, since comments are free. The reason may be that s/he cannot answer the question (which was not the case here) or because asker does seem cooperative or polite etc... X911: jerk does come into play H: Indeed - it allows people to adjust, grab something or tension up their muscles. It just does not topple people, it just allows the toppling force to surprize them. X911: I noticed you deleted your rude posts H: I deleted nothing. If you re-read the dialog, you will notice who was calling people names. (In spite of my handle, I am actually a human being, not a hedgehog). conclusion: If you use the sketched up algorithm - you need to check the factors,like is it a/j or 2a/j or 4a/j or so, and really understand the solution. Sketch is not intended to be a full solution. This, limited answer is free. If your consciousness will move you so, you may same some money to a charity, victims of civil wars - perhaps. H. |
Subject:
Re: Physics of a Subway Train
From: x911gt2-ga on 29 Apr 2005 09:26 PDT |
You were the one who flipped out on me. Remember? And yes, you deleted the comments that you made in the first place that started this whole debacle. If you didn't, then why is your comment that WAS between phil's comments at 8:18 and 9:50 missing? Anyways, like I said before, I don't want your answers or your input. So, please do us both a favor and move on. You already made your impression and you can't change it. You're lucky I don't report you to google. I would, except for the fact that your exceptionally rude post is suddenly *missing*. |
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