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Q: Expressing the Volume of a Hyperboloid in terms of the area of two ellipses ( No Answer,   0 Comments )
Question  
Subject: Expressing the Volume of a Hyperboloid in terms of the area of two ellipses
Category: Science > Math
Asked by: danielvogel-ga
List Price: $4.50
Posted: 04 May 2005 16:22 PDT
Expires: 05 May 2005 01:15 PDT
Question ID: 517860
Hey I'm trying to solve the "easy" part of a problem, but I just can't
do it. I need help.

I have a hyperboloid: (x^2/a^2)+(y^2/b^2)-(z^2/c^2)=1

First I'm asked to find the volume of this from z=0 to z=h. To do
this, I find the cross sectional area and integrate it from 0 to h.

So, since the area of an Ellipse is pi*a*b, i get that the cross
sectional area of this hyperboloid is A=(pi*a*b/c^2)*(c^2+z^2)

So if I integrate (from z=0 to z=h), I get that V=[pi*a*b*h/(3c^2)]*(3c^2+h^2)



So far so good, now I'm asked to find the Volume in terms of A(0) (the
area of the ellipse at z=0) and A(h) (the area of the ellipse at z=h)

I know that A(0)=pi*a*b
and that A(h)=(pi*a*b/c^2)(c^2+h^2)

Now how do I express the volume of the hyperboloid from z=0 to z=h in
terms of A(0) and A(h)??? I know its simple algebra but i just can't
do it...
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