Hi jay1942:
Thanks for the interesting question.
I have pulled/calculated the following information from:
What Are the Odds of That?
URL: http://www.dicesetter.com/irish/irisharticle12e.htm
To review, a "horn high aces" bet is:
"If you don't already know what it is, a "Horn High" bet is a horn
bet, with an additional wager on a specific horn number. So a "$5
Horn High Yo" is horn bet with $1 each on 2,12, and 3 and $2 on the
eleven. You can also have "Horn High Ace-Duece", "Horn High 12" or
"Horn High Aces". Frankly, I think most people who make Horn High
bets haven't the vaguest idea what they're supposed to be paid. If
you're in a sawdust joint where there are a lot of break in dealers,
you'd better know the payoffs or in all likelihood, you'll be
underpaid."
So, a "horn high aces" bet is 2/5 on 2, and 1/5 on each of 3, 11, and
12. The amount of the payoff depends on what was rolled. so for a $90
wager, there would be $36 on 2 and $18 on each of 3, 11, and 12.
If a two (aces) is rolled:
Formula = 11 x wager + amount on the 2
= 11 * $90 + $36
= $1026
If a 3 or 11 is rolled:
Formula = 2 x wager plus amount on # that rolled
= 2 * $90 + $18
= $198
If a 12 is rolled:
Formula = 5 x wager plus amount on 12
= 5 * $90 + $18
= $468
As a side note, the expected return (i.e., the amount you can be
expected to win on average for a $90 wager on "horn high aces" is:
expected return = (1/36) * $1026 + (1/9) * $198 + (1/36) * $468
= $28.50 + $22 + $13
= $63.50
So, like most all bets in gambling, "horn high aces" doesn't pay
particularly well over the long run.
Search Strategy (on Google):
* "horn high aces" craps
Hope this helps.
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