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 Subject: craps Category: Sports and Recreation > Games Asked by: jay1942-ga List Price: \$2.50 Posted: 18 May 2005 19:56 PDT Expires: 17 Jun 2005 19:56 PDT Question ID: 523184
 `what is the payoff on a \$90 horn high aces bet ?`
 ```Hi jay1942: Thanks for the interesting question. I have pulled/calculated the following information from: What Are the Odds of That? URL: http://www.dicesetter.com/irish/irisharticle12e.htm To review, a "horn high aces" bet is: "If you don't already know what it is, a "Horn High" bet is a horn bet, with an additional wager on a specific horn number. So a "\$5 Horn High Yo" is horn bet with \$1 each on 2,12, and 3 and \$2 on the eleven. You can also have "Horn High Ace-Duece", "Horn High 12" or "Horn High Aces". Frankly, I think most people who make Horn High bets haven't the vaguest idea what they're supposed to be paid. If you're in a sawdust joint where there are a lot of break in dealers, you'd better know the payoffs or in all likelihood, you'll be underpaid." So, a "horn high aces" bet is 2/5 on 2, and 1/5 on each of 3, 11, and 12. The amount of the payoff depends on what was rolled. so for a \$90 wager, there would be \$36 on 2 and \$18 on each of 3, 11, and 12. If a two (aces) is rolled: Formula = 11 x wager + amount on the 2 = 11 * \$90 + \$36 = \$1026 If a 3 or 11 is rolled: Formula = 2 x wager plus amount on # that rolled = 2 * \$90 + \$18 = \$198 If a 12 is rolled: Formula = 5 x wager plus amount on 12 = 5 * \$90 + \$18 = \$468 As a side note, the expected return (i.e., the amount you can be expected to win on average for a \$90 wager on "horn high aces" is: expected return = (1/36) * \$1026 + (1/9) * \$198 + (1/36) * \$468 = \$28.50 + \$22 + \$13 = \$63.50 So, like most all bets in gambling, "horn high aces" doesn't pay particularly well over the long run. Search Strategy (on Google): * "horn high aces" craps Hope this helps. websearcher```
 jay1942-ga rated this answer: `very good answer thank you.`