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Q: math/statistics/probability ( Answered 4 out of 5 stars,   2 Comments )
Subject: math/statistics/probability
Category: Science > Math
Asked by: marine74-ga
List Price: $2.00
Posted: 18 Jun 2005 11:18 PDT
Expires: 18 Jul 2005 11:18 PDT
Question ID: 534582
given eight students, three of which are females, if two students are
selected at random, without replacement, what is the probability that
both students are female?
Subject: Re: math/statistics/probability
Answered By: richard-ga on 19 Jun 2005 06:06 PDT
Rated:4 out of 5 stars
Hello and thank you for your question.

The answers given in the comments are correct.

Here's an analysis that may make it clearer how this works:

On the first pick, there are 3 winning picks out of 8 possibilities,
so that's a 3/8 chance of being successful so far.

On the second pick, assuming the first pick ws successful, there are 2
winning picks out of 7 possibilities, so that's a further 2/7 chance.

Since you have to win both the first and second pick, the overall
probability is the product of 3/8 and 2/7 = 6/56 which simplifies to

For a more complete explanatation, take a look at

Search terms used:
probability both students female

Good luck with your studies
marine74-ga rated this answer:4 out of 5 stars

Subject: Re: math/statistics/probability
From: dkappad-ga on 18 Jun 2005 16:47 PDT
3/28      i wonder how i get an account that can answer questions in
stead of comment...
Subject: Re: math/statistics/probability
From: gone2ucf-ga on 18 Jun 2005 21:57 PDT
Total outcomes, selecting 2 at a time, male or female, is 28.
Probability of randomly selecting 2 females out of the 28 is 

 (3)     ---------
 (2)      2!(3-2)!      3
----- = ------------ = ---- = .1071
 28         28          28

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