

Subject:
math/statistics/probability
Category: Science > Math Asked by: marine74ga List Price: $2.00 
Posted:
18 Jun 2005 11:18 PDT
Expires: 18 Jul 2005 11:18 PDT Question ID: 534582 
given eight students, three of which are females, if two students are selected at random, without replacement, what is the probability that both students are female? 

Subject:
Re: math/statistics/probability
Answered By: richardga on 19 Jun 2005 06:06 PDT Rated: 
Hello and thank you for your question. The answers given in the comments are correct. Here's an analysis that may make it clearer how this works: On the first pick, there are 3 winning picks out of 8 possibilities, so that's a 3/8 chance of being successful so far. On the second pick, assuming the first pick ws successful, there are 2 winning picks out of 7 possibilities, so that's a further 2/7 chance. Since you have to win both the first and second pick, the overall probability is the product of 3/8 and 2/7 = 6/56 which simplifies to 3/28. For a more complete explanatation, take a look at http://faculty.vassar.edu/lowry/ch5pt2.html Search terms used: probability both students female Good luck with your studies Richardga 
marine74ga rated this answer: 

Subject:
Re: math/statistics/probability
From: dkappadga on 18 Jun 2005 16:47 PDT 
3/28 i wonder how i get an account that can answer questions in stead of comment... 
Subject:
Re: math/statistics/probability
From: gone2ucfga on 18 Jun 2005 21:57 PDT 
Total outcomes, selecting 2 at a time, male or female, is 28. Probability of randomly selecting 2 females out of the 28 is 3! (3)  (2) 2!(32)! 3  =  =  = .1071 28 28 28 
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