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Q: Bernoulli Principel ( No Answer,   4 Comments )
Question  
Subject: Bernoulli Principel
Category: Science > Physics
Asked by: anewwaytopush-ga
List Price: $2.00
Posted: 21 Jun 2005 10:19 PDT
Expires: 21 Jul 2005 10:19 PDT
Question ID: 535523
I have been told that Bernoulli Principel works different above a 1/3
the speed of sound and different formula would be needed. What is that
formula?
Answer  
There is no answer at this time.

Comments  
Subject: Re: Bernoulli Principel
From: mettle-ga on 21 Jun 2005 11:58 PDT
 
I don't remember exactly, but basically, at sonic speed (things around
the speed of sound) there are a different set of formulas that you can
find in any Fluid Mechanics engineering text book. Above the speed of
sound, the equation is basically reversed and the equivalent of
putting your finger over the mouth of a hose slows down the fluid
velocity instead of speeding it up.
Subject: Re: Bernoulli Principel
From: anewwaytopush-ga on 24 Jun 2005 17:20 PDT
 
To mettle-ga;
Sounds like you are thinking more of the head pressure and I need to
know about the pressure normal to the surface.
All my books say nothing about high speed.
This is in reference to www.newlifter.com
Subject: Re: Bernoulli Principel
From: jagad-ga on 26 Jun 2005 21:44 PDT
 
According to classical mechanics BERNOULIES PRINCIPLE does not change
according to the speed of the object concerned but it is a well known
fact that the motion of a body is affected by its velocity.Now i
cannot provide u the answer but tomorrow i will solve it.
Subject: Re: Bernoulli Principel
From: hfshaw-ga on 28 Jun 2005 12:49 PDT
 
Bernoulli's Principle is really just a statement of the conservation
of energy.  Bernoulli's Principle is embodied in the Bernoulli
equations, which are special cases of the Navier-Stokes equations, the
fundamental equations that describe flow in fluids.  There are various
forms of the Bernoulli equations (i.e., for steady incompressible
flow, steady compressible flow, time-dependent compressible or
incompressible flow, etc.), depending on which of various possible
simplifying assumptions are made in deriving them.  The common form
that you are probably thinking of, and that is presented in most
introductory textbooks, applies to laminar, steady-state flow of an
incompressible fluid with constant density and zero viscosity:

		p/D + 1/2*v^2 + g*z = constant

where p is the pressure, D is the density, v is the fluid speed, g is
the gravitational acceleration, and z is the height.

At low speeds, the assumption that a fluid like air is
incompressibleis pretty good; however as the speed increases, this
assumption becomes increasingly bad.  At a Mach number of about 0.3,
the density of the fluid will change by several percent relative to
the reference (zero speed) density.  This problem is probably what you
are referring to in your question.

To account for this, one has to relax the requirement that the fluid
be incompressible and derive a Bernoulli equation for compressible
fluids.  A common way to do this is to assume instead that the
*entropy* of a parcel of fluid is constant as it travels along its
path (i.e., that the fluid follows an adiabatic path).  Doing this
results in the most common form of the Bernoulli equation for
compressible flows:

		h + 1/2*v^2 + g*z = constant

where h is the enthalpy of the fluid, and the other variables have the
same meaning as before.

A good reference for all this stuff is Professor M.S. Cramer's website
on fluid dynamics at http://www.navier-stokes.net/nsintro.htm

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