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Subject:
Forecasting value of an used car in Excel
Category: Science > Math Asked by: marcus_venturi-ga List Price: $3.00 |
Posted:
07 Jul 2005 03:20 PDT
Expires: 12 Jul 2005 23:44 PDT Question ID: 540856 |
Hello, What do you think is the best formula to calculate in Excel an extimated value in january 1st 2008 of the used car bought new in july 1st 2004, only having the following data of it? (today value - new: $9900) today's value - used car bought new in july 1st 2004: $6200 today's value - used car bought new in january 1st 2004: $5700 today's value - used car bought new in july 1st 2003: $5200 I would like to find a formula that doesn't return a negative value if I use it for example on an extimation on 1/1/2100 instead of 1/1/2008, like the standard forecast formula do. Any ideas? Thanks in advance |
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There is no answer at this time. |
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Subject:
Re: Forecasting value of an used car in Excel
From: manuka-ga on 07 Jul 2005 18:56 PDT |
Use the GROWTH function: =GROWTH(B2:B5,A2:A5,A6,TRUE) where A2:A5 are the known times (date of purchase, DOP + 1 year, DOP + 18 months, DOP + 2 years) and B2:B5 are the known prices (9900, 6200, 5700, 5200), and A6 is the forecast date. Using this formula, with the data of purchase 1 July 2004, I get the value on 1/1/2008 to be $3013.48 and the value on 1/1/2025 to be $11.91. On 1/1/2100 it drops down to $0.0000000003. |
Subject:
Re: Forecasting value of an used car in Excel
From: marcus_venturi-ga on 11 Jul 2005 08:47 PDT |
Hi, I tried but it seems to not work as I expect. What is not working correctly? why do it give a 51665.68? 01/07/2004 ? 6200.00 01/01/2004 ? 5700.00 01/07/2003 ? 5200.00 01/01/2003 ? 51665.68 (=GROWTH($A$1:$A$3;$B$1:$B$3;A4;TRUE)) |
Subject:
Re: Forecasting value of an used car in Excel
From: woodenspoon-ga on 12 Jul 2005 11:12 PDT |
It looks like you lose a big chunk in year 1 (of 3700), then 1000 per year (so 500 each half year). So you buy in jul04 at about 9900 (or about 9700 if you think what the new price was in jul2004, and add "reverse inflation" at 2pc). Then lose 3700, then lose 500 per half year. So by jan08 after 6 lots of 500 you have a car worth about 3000. I'm not convinced that a more complex model would be helpful - prediction way out of your data set is never a great plan, and you should think about checking that the model you use is working properly... |
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