Creating a perpetual calendar: a math question?
Asked by: k8hayes-ga
List Price: $2.00
28 Jul 2005 13:40 PDT
Expires: 27 Aug 2005 13:40 PDT
Question ID: 549108
I have a perpetual calendar that only has five rows. Therefore, in some months, such as this one (July 2005), I run out of room for the "31" tile. I want to make my own tiles that allow one day to include split dates, e.g., 24/31 for this month, which would go in the Sunday slot at the beginning of the bottom row. Here's my question: Is there a way to figure out how many of those types of tiles I will need, and which number combinations, to make the calendar ready for any month forever?
Re: Creating a perpetual calendar: a math question?
Answered By: mathtalk-ga on 28 Jul 2005 17:53 PDT
Hi, k8hayes-ga: If the days of the week are fixed at the top of the five row calendar, then the "worst case" is the first of a month on a Saturday and 31 days in the month. In this case the last "week" in the month will consist of a Sunday the 30th and a Monday the 31st. So you will only need two "split" tiles, a 23/30 and a 24/31. October 2005 will be just such a month. If you were allowed to "rotate" the days of the week, then the days of the month could always be fitted to five rows without using "splits". I admit to finding a calendar that changes the days of the week around, e.g. business calendars that start on Mondays, confusing to look at though. regards, mathtalk-ga
rated this answer:
and gave an additional tip of:
Thanks so much! Yup, the days are fixed, and I don't think I could stand it if they were moved around anyway! ;O) But that's all I needed!
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