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Q: Hydraulic Pressure over a dispersion area ( No Answer,   2 Comments )
Question  
Subject: Hydraulic Pressure over a dispersion area
Category: Science > Physics
Asked by: msarte-ga
List Price: $10.00
Posted: 08 Aug 2005 09:34 PDT
Expires: 10 Aug 2005 09:12 PDT
Question ID: 553089
How would I go about finding the Output pressure of a hydraulic pump
at specific intervals(1cm intervals out to 60cm) if I have a dispersion angle of
25 degrees and a pressure of 2800PSI at 0cm. I basically just need the
information on what formula to use for this type of problem.

Request for Question Clarification by redhoss-ga on 08 Aug 2005 17:42 PDT
The pressure a hydraulic pump will produce is normally only limited by
the strength of the components, the amount of power available, and the
settings of any pressure limiting devices. What type of pump are you
speaking of and can you define "dispersion angle". It sounds like you
might be talking about a radial piston pump, but I am not familiar
with the term "dispersion angle". Could you be talking about the
swashplate angle and how it relates to displacement.

Clarification of Question by msarte-ga on 08 Aug 2005 21:52 PDT
I was given this problem by my girlfriends uncle and it was scribbled
on a napkin. He did not provide a specific type of hydraulic pump but
basically the diagram he drew was to figure out the change in pressure
over an expanding area. The diagram was basically a triangle that
opened from the pump at a 25 degree angle. He did not tell me if it
was a sealed system or an open system. I am going to assume its a
sealed system but either way this problem might be bull****. I am just
going into engineering so I really have no clue how to solve this or
if its possible. If its sealed then wouldn't the pressure be the same
at all points? or If it was open wouldn't the pressure be equal to
atmospheric pressure? This is very open ended so any sort or solution
or guide to the solution will be welcomed.

Clarification of Question by msarte-ga on 09 Aug 2005 09:45 PDT
redhoss feel free to claim the 10$ :-D
Answer  
There is no answer at this time.

Comments  
Subject: Re: Hydraulic Pressure over a dispersion area
From: myoarin-ga on 09 Aug 2005 08:18 PDT
 
Hi Msarte,
Let's assume he was talking about a closed system.  If I understand
your description correctly, we're looking at a funnel with the wide
end covered sealed shut) and the liquid under pressure of 2800 psi
applied at the small end of the funnel.  Furthermore, he is suggesting
that the pressure at the broad circular sealed end of the funnel
varies  - perhaps higher in the center and diminishing towards the
circumference.   Okay?  Since he didn't provide a better description,
we can claim this is right.

I think he is trying to trick you, but uncles of favorite nieces can
be like that.  ;)

You are right, the pressure is the same at all points.

The answer to this question applies:  
http://answers.google.com/answers/threadview?id=541262

Myoarin
Subject: Re: Hydraulic Pressure over a dispersion area
From: redhoss-ga on 10 Aug 2005 08:33 PDT
 
I wouldn't think of taking your $10. I didn't understand your
question. I think that, after reading your clarification,  myoarin-ga
has given you a good answer. Too bad he can't accept your payment.
Shame on your girlfriend's uncle for trying to twist your mind.

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