Google Answers: Search engine find javascript code

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Q: Search engine find javascript code ( No Answer, 0 Comments )

Question

Subject: Search engine find javascript code
Category: Computers > Software
Asked by: drormata-ga
List Price: $50.00

Posted: 28 Sep 2005 15:04 PDT
Expires: 03 Oct 2005 12:41 PDT
Question ID: 573957

I know that as a rule search engine focus on the human visible part of
a web page. I would, however, like to be able to either:
1. Search the javascript code. It's ok if the search engine only looks
at the code that's only in the <body> part of the page.
2. Search for sites that include a certain javascript or CSS page. For
instance sites that include foo.js by doing
 <script type="text/javascript" src="foo.js"></script>

Ideally one of the free search engines would provide this capability,
but please include in your answer any paid services that offer this
capability.

Request for Question Clarification by pafalafa-ga on 28 Sep 2005 19:34 PDT

I'm not sure I'm getting what you're after here.  Do you want a search
on code that appears as part of the text of a site?  Or are you trying
to search on code that is generally invisible to the search bots?

For instance, here's a search on "src="foo.js"":


://www.google.com/search?sourceid=navclient&ie=UTF-8&rls=GGLD,GGLD:2005-04,GGLD:en&q=%22src%3D%22foo%2Ejs%22%22


Are these results of interest at all, or are they of no use whatsoever.


pafalafa-ga

Clarification of Question by drormata-ga on 28 Sep 2005 21:30 PDT

No, this doesn't really help because it will only find things where
"src=foo.js" is part of the *text* of the web page. I actually want to
actually look for the javascript code. So assume a web page has
something like the following HTML code:
<HTML>
<head>
 <script type="text/javascript" src="foo.js"></script>
</head
<body>
<h1> My Page </h1>
<script type='text/javascript'>
//foo.js defines function bar
var myVar getElementById('abc');
bar(myVar);
</script>
</body>
</HTML>

I'd like to find this page either by finding that it includes foo.js
or by finding that it uses the function bar.

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