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Subject:
Star-delta / Wye-Delta Circuit Transformation
Category: Science > Physics Asked by: kenchatfield-ga List Price: $10.00 |
Posted:
30 Sep 2005 06:35 PDT
Expires: 30 Sep 2005 10:58 PDT Question ID: 574596 |
Can someone explain to me how the equations for the star-delta circuit transformation are derived? (refer to http://en.wikipedia.org/wiki/Y-delta_transform) I am interested in the transform from the delta arragement to the star. Using the symbols defined on the linked page, to derive R1, R2 and R3 in terms of Ra, Rb and Rc I presume you have to consider the resistance between each of the terminals in turn. Doing this I get: Ra=R1+R3 Rb=R1+R2 Rc=R2+R3 Which, when solved, gives an equation for the resistors of: R1=0.5(Ra+Rb-Rc) R2=0.5(-Ra+Rb+Rc) R3=0.5(Ra-Rb+Rc) Which is incorrect. I guess there must be a fault in my logic at step 1! How do you correctly evaluate the resistances between points x, y and z? |
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There is no answer at this time. |
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Subject:
Re: Star-delta / Wye-Delta Circuit Transformation
From: rracecarr-ga on 30 Sep 2005 09:47 PDT |
You are leaving out one of the paths current can follow in the delta circuit. Current can flow from x to z say through Ra, as you've accounted for, but also the 'long way' through both Rb and Rc. So instead of Ra = R1 + R3, you need to calculate the actual impedence between x and z in the delta circuit. To do that: 1/Rxz = 1/Ra + 1/(Rb + Rc) = (Ra + Rb + Rc) / (Ra (Rb + Rc)) So: Ra(Rb + Rc) / (Ra + Rb + Rc) = R1 + R3 You can derive similar equations for the impedences between the other two pairs of points, and solve the system. |
Subject:
Re: Star-delta / Wye-Delta Circuit Transformation
From: kenchatfield-ga on 30 Sep 2005 10:58 PDT |
Bump! Thanks very much... I must have been busy sleeping when I was trying to figure that one out! |
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