Could u please check my answer is right or wrong?

1. A hiker leaves camp and, using a compass, walks 4km East, 6km
South, 3km East, 5km North, 10km West, 8km North, 3km South. At the
end of three days, the hiker is lost. By drawing a fiagram, compute
how far the hiker is from camp and which direstion should be taken to
get back to camp.
----distance= 5km, direction= 53 degrees.

2.A dog searching for abone walks 3.5 m South, then 8.2m at the angle
of 30 degrees North of East, and finally 15m West. Find the dog's
displacement vector.
---D=11.5m or 1.93m
---Direction=-18 or -4.3 degrees.

3. Find the resultant of the following set of forces:
a.200N @ 53 degrees

4. A cannon sitting on the battlement of a castle is aimed away from
the castle at an angle theta above the horizontal. Find the equation
for a time for the cannonball to hit the level ground below in terms
of the height of the battlement, the magnitude and direction of the
initial volocity, and acceleration due to gravity.

1. 5km is correct. I see how you got 53 degrees, but it is about 53
degrees south of east. The exact heading is 306.87 degrees or if you
round-off 307 which kind of agrees with your answer of 53 degrees.

2. Something is wrong here. I get 7.92 @ 175.66. One of us is wrong. I
cheated and did a CAD layout.

It seems like home assignment so I will just give hints:
1) 5 kms is correct.
About 53 degrees, 53 degrees is the effective direction he travelled.
You have to calculate the angle he should travel to GET BACK.
Also, above answers are valid only if you are far from the poles. If
you are very near the pole, for example, you can travel 4 kms east and
return to the same spot after completing the circle.
2) and 3) are similar to 1)

4) The time to hit the ground is independent of horizontal velocity
and horizontal forces.
* Calculate the initial vertical velocity (upwards).
* Vertical acceleration is g (downwards)
* Use h = v(init)*t + (1/2)*t*t,
h = 0 in this case.

Have fun!