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Q: Trigonometric Functions ( Answered 5 out of 5 stars,   2 Comments )
Question  
Subject: Trigonometric Functions
Category: Science > Math
Asked by: 3eb-ga
List Price: $35.00
Posted: 22 Nov 2005 18:26 PST
Expires: 22 Dec 2005 18:26 PST
Question ID: 596522
I would like to know when to use specific trig functions in word
problems and why.  For example, let's say I have a tree, from a point
115 feet from the base of the tree, the angle of elevation to the top
of the tree is 64.3 degrees.  Find the height of the tree to the
nearest foot.  In my precalculus class we used the Tangent function,
to get a result of approx. 239 feet.  Now why did we use this
function?  I would like examples of different problems, which trig
functions used, and why.  Thank you very much for your help.

Clarification of Question by 3eb-ga on 22 Nov 2005 18:41 PST
Just a clarification, to start me in the right direction all I need
now is Trig functions of Acute angles.
Answer  
Subject: Re: Trigonometric Functions
Answered By: answerguru-ga on 22 Nov 2005 19:05 PST
Rated:5 out of 5 stars
 
Hi 3eb-ga,

Thanks for your question - the first step when looking at this type of
problem is to draw out what is being described. Since trigonometry is
the calculation of distance and angles of right triangles, we can
always classify each side of the triangle relative to a given angle.
Remember that each right triangle contains two legs and a hypotenuse.

In your example you are given an angle of 64.3 degrees. After drawing
this out you can see that this angle is opposite to the tree.
Therefore the leg of the right triangle represented by the tree is
called the "opposite" side.

Since we know the opposite side, we can then label the "adjacent
side", which is the other leg of the triangle. This is the side of the
triangle represented by the ground (we know the value of this side is
115 feet).

The tangent of an angle is a ratio of (opposite side / adjacent side),
or for short:

tan(x) = opp/adj

tan(64.3 deg) = opp/115

115*tan(64.3) = opp

opp = 238.95 feet

Now in addition to the tangent, there are two other common trig
functions called sine and cosine.

Sine of an angle is the ratio of the opposite side to the hypotenuse.
The formula is:

sin(x) = (opposite side / hypotenuse) = opp/hyp

We would use the sine function when we are given an angle and need to
determine either the opposite side or the hypotenuse (where we are
given the other side in the question).

Cosine of an angle is the ratio of the adjacent side to the
hypotenuse. The formula is:

cos(x) = (adjacent side / hypotenuse) = adj/hyp

We would use the cosine function when we are given an angle and need
to determine either the adjacent side or the hypotenuse (where we are
given the other side in the question).

Here are the steps to following general:

1. Draw out a diagram of the problem using the information in the question

2. Based on the angle that you are given, label the sides of the right
triangle (opposite, adjacent, and hypotenuse). With some practice you
will be able to identify the sides without labelling them.

3. Identify which side you want to calculate, and then select the
correct trig function to use based on the information you've been
provided. So if you have an angle and an adjacent side and need to
calculate the hypotenuse, the only equation that works is cosine.

4. Plug the information you have into the appropriate equation and
solve for the desired variable.

As a rule for this type of question, you will always be given one
angle and the distance of one leg. I believe what confuses most people
is the identification of the different sides. Once you can do that, it
is just a matter of identifying what you have, what you are looking
for, and solving the equation that uses all three pieces of
information.

I hope this has given you a deeper understanding of the basic
trigonometric functions. If you have problems understanding any of the
information above, please post a clarification and I will respond
promptly.

Thanks for using Google Answers!

Cheers,
answerguru-ga

Request for Answer Clarification by 3eb-ga on 23 Nov 2005 08:34 PST
Thank you for the 3 main functions, but could you please include
Cosecant, Secant, and Cotangent.  Please include examples of each, and
I'll include a tip.  Thanks again for your prompt attention.

Clarification of Answer by answerguru-ga on 23 Nov 2005 11:18 PST
Hi 3eb-ga,

In response to your clarification I am including details on Cosecant,
Secant, and Cotangent. These were not originally included because they
are simply alternate formulas.

The cotangent of an angle is a ratio of (adjacent side / opposite
side), or for short:

cot(x) = adj/opp

We would use the cotangent function when given an angle and need to
determine either the opposite or adjacent side (where we are given the
other side in the question). This is the same condition as tangent, so
you could use either one.

Using your original tree example, you could easily solve the problem
using cotangent:

tan(64.3) = opp/115
1/tan(64.3) = 115/opp
cot(64.3) = 115/opp
opp = cot(64.3)/115
opp = 238.95 feet

Cosecant of an angle is the ratio of the hypotenuse to the opposite
side. The formula is:

csc(x) = (hypotenuse / opposite side) = hyp/opp

The relationship between sine and cosecant is:

csc(x) = 1/sin(x)

We would use the cosecant function when we are given an angle and need
to determine either the opposite side or the hypotenuse (where we are
given the other side in the question). This is the same condition as
cosine, so you could use either one.

Secant of an angle is the ratio of the hypotenuse to the adjacent
side. The formula is:

sec(x) = (hypotenuse / adjacent side) = hyp/adj

The relationship between cosine and secant is:

sec(x) = 1/cos(x)

We would use the secant function when we are given an angle and need
to determine either the adjacent side or the hypotenuse (where we are
given the other side in the question). This is the same condition as
cosine, so you could use either one.

Cheers,
answerguru-ga
3eb-ga rated this answer:5 out of 5 stars and gave an additional tip of: $5.00
Thank you very much for the quick response.  The information given
will be of much help!

Comments  
Subject: Re: Trigonometric Functions
From: fred709394-ga on 29 Nov 2005 13:34 PST
 
If 3eb-ga is at high school level, I can accept the definition of
sin(x), cos(x) and tan(x) only if the right-angle triangle is used to
define the three sides.

If 3eb-ga is at college level, I would suggest using the unit-circle
to define the trigonometic function.
Subject: Re: Trigonometric Functions
From: stevenpatrick-ga on 03 Feb 2006 18:45 PST
 
I have found a small error in the answer to the trig function...

Look at step 4

tan(64.3) = opp/115
1/tan(64.3) = 115/opp
cot(64.3) = 115/opp
    opp = cot(64.3)/115
opp = 238.95 feet


It should be  opp=115/cot(64.3)
But somehow 238.95 feet is the right answer.


Here is just a quick formula sum up.

(cosX)^(-1)=secX
(sinX)^(-1)=cscX
(tanX)^(-1)=cotX

For more useful information go here...


http://en.wikipedia.org/wiki/Trigonometric_functions

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