How would the period of a simple pendulum be affected if it was
located on the moon instead of the earth?

Howdy liskris-ga,

The Future Scientists and Engineers of America (FSEA) website has the
answer to your question.

"PENDULUM CLOCK SCIENCE CHALLENGE"
http://www.fsea.org/pdf/questions/PC1QA.pdf

"The period of a pendulum on the moon would be longer, shorter or the
same as on the earth?
...
The period would be longer since the force of gravity is less."

If you need any clarification, please feel free to ask.


Search strategy:

Google search on: period pendulum moon Earth
://www.google.com/search?q=period+pendulum+moon+Earth

Looking Forward, denco-ga - Google Answers Researcher

It would be nice to be a bit more quantitative, don't you think?

If you take the second link returned from your search as of the time I
write this (or no doubt many others - it was the first one I tried),
you will find that the period varies as sqrt(L/g) where L is the
length of the pendulum and g the local strength of gravity. Since the
Moon's gravity is about 1/6 that of Earth, the period on the Moon
would be about sqrt(6) or roughly 2 1/2 times longer than the period
on the Earth.

Sure, but for a low priced question, an absolutely correct answer with
usable links is very satisfactory  - and allows the questioner the
opportunity to ask for clarifications or to do a little thinking of
his/her own.

It would be a lot longer on the Moon because NO air resistance and weak gravity.
On the Earth air and gravity are much stronger.