If something goes up, does it stop before it comes down or does it
change direction without a ceasession of motion?

if I remember right it is at Zero Gravity for an instant, so for that
instant it would be stopped.  Velocity would be Zero if goint strait
up.  if it is arched then it doesn't stop

If something goes up, does it stop before it comes down or does it
change direction without a ceasession of motion?
 

ANSWER:
Yes.  Theoretically, the object will come to a stop before coming
down.  But it will remain stopped for only an instant - or an
infinitely small amount of time.  The object theoretically has a
velocity = 0 at the top.  However, the ball does not remain stopped
for any length of time at all... (or exactly 0 seconds.)
For proof of this, read about the Intermediate Value Theorem, by the
way... http://mcraefamily.com/MathHelp/CalculusTheorem1IntermediateValue.htm

Just wanted to add one more thing...
Only the vertical motion will stop.  If the object has any horizontal
motion, the horizontal motion will remain constant, but the vertical
motion will still stop instantaneously.

Hope that helps!

If you toss an object up and it comes back down, then certainly at
some point its upwards motion must stop and be replaced with downwards
motion. If we restrict the problem to very close to sea level, so that
we needn't be bothered with the complication of the strength of
gravity growing weaker with altitude, then we can say the following:

   An object under the influence of gravity is under constant
acceleration downwards. Even sitting still on a shelf, a baseball is
perpetually accelerating downwards. (But, in this case, also being
equally accelerated upwards by the shelf, so that the velocity remains
constant.) If I project ("toss") the ball upwards, its downwards
acceleration continues. It starts moving up at some velocity, but that
up-velocity gets eaten away constantly by the opposing acceleration,
which always increases its velocity in the opposite direction. So it
starts out at some rate, and it steadily slows, approaching zero.

   Exactly how high it gets before actually reaching zero velocity
depends on how fast it's going when it starts. But it does drop
smoothly to zero and immediately reverses itself, starting from that
point at zero and accumulating velocity as it returns. Ideally
(meaning, with no complications, such as air resistance) the change in
velocity coming down is an *exact* reversal of the velocity change on
the way up. This means that you could play a movie of it going either
way backwards and you couldn't tell the difference.

If is goes up fast enough, it will achieve escape velocity and not
stop or come back down at all.  Otherwise I would have to agree with
bcreid83-ga.

I you throw a rock directly up with certain force, it continues to go
upwards until gravity has slowed it down to zero. Then it drops back
to ground with approximately same speed than it was thrown. For
example if you throw a rock with starting speed of 9,81 m/s, and
gravity pulls it downwards 9,81 m/s^2, it means that gravity
deaccelerates speed of thrown rock to zero in one second. Then it
starts to accelerate rock backwards to ground same time as it took to
get up. After one second of free falling rock has speed of 9,81 m/s^2,
which was same as starting speed. There is several presumptions in
this example. First is that there is no other forces affecting to the
rock like air resistance. Another is that the rock is thrown at ground
level, so that rock falls as long time as it went up.

every object that thrown upwards freely will reach to a point at an
instant where its velocity will be zero. when the velocity is zero
then the object has no kinetic energy to beat the pulling of the
gravity, also the potential energy of the object increases as it
climbs upwards causing it to fall back.

every object that thrown upwards freely will reach to a point at an
instant where its velocity will be zero. when the velocity is zero
then the object has no kinetic energy to beat the pulling of the
gravity, also the potential energy of the object increases as it
climbs upwards. thus, increasing potential energy plus the weight
cause the object to stop.

I disagree with qed100's comment that "Even sitting still on a shelf,
a baseball is perpetually accelerating downwards." Clearly it is not
accelerating at all, as it has a constant velocity of zero. What
qed100 means is that the force of gravity is perpetually pulling it
downward. However the shelf is pushing upward, making no net force and
hence, given F=ma, since F is zero then so is a.

Thank you all very much for the comments. This is exactly where we all
went with our debate. We could not, however, agree on the length of
time the object was stopped.
If it is stopped, as bcreid83 says, for 0 seconds, "However, the ball
does not remain stopped for any length of time at all... (or exactly 0
seconds.)", and this is the other side of the argument, then can we
not apply that same time interval, 0 seconds, to any part of the path
of travel of the object, not just the apex, and see that the object
has stopped?

There is no mystery regarding the fact that an object thrown upward
momentarily has zero vertical velocity during its parabolic arc. This
is precisely the point where the graph of velocity versus time, which
is a straight line, crosses the horizontal axis.

Your last comment evokes the very old (several centuries B.C.) Zeno's
Paradoxes concerning motion. Modern mathematics, especially real
analysis, has resolved the philosophical dilemmas that troubled
philosophers for so many centuries. The well-defined concepts of
limits, continuity, etc., have been worked into a consistent and
paradox-free framework. I would urge you to examine these topics.