Google Answers Logo
View Question
 
Q: scientific instruments ( No Answer,   1 Comment )
Question  
Subject: scientific instruments
Category: Science
Asked by: radmadscientist-ga
List Price: $5.00
Posted: 10 Dec 2005 11:01 PST
Expires: 09 Jan 2006 11:01 PST
Question ID: 604125
What does Electron paramagnetic resonance observe and how?
Answer  
There is no answer at this time.

Comments  
Subject: Re: scientific instruments
From: hfshaw-ga on 14 Dec 2005 11:39 PST
 
Do a Google search on "electron paramegnetic resosonance", and you'll
get numerous hits that have basic to advanced explanations of this
technique.   EPR is also known as electron spin resonance.

Briefly, electrons have a quantum property known as "spin", which
gives rise to a magnetic moment for the electron.  (You can crudely
think of each electron behaving like a bar magnet.)  Like other
properties of quantum systems, an electron's spin can only take on
certain discrete values, in this case, +1/2 or -1/2.  Using the
analogy to a bar magnet, these correspond to having the north pole of
the magnet pointed in one direction, or in exactly the opposite
direction.

In the absence of another magnetic field, there is no difference in
energy between these two different orientations, but if one imposes an
external magnetic field, then one spin orientation will have lower
energy (corresponding to the case in which the N pole of a bar magnet
is pointed at the S pole of the magnet producing the external field --
in this case the poles *attract* one another), and the other
orientation will have higher energy (corresponding to the case in
which the N pole of a bar magnet is pointed at the N pole of the
external magnet -- in this case the poles *repel* one another).  The
stronger the external magnetic field, the larger the difference in
energy between the two possible "states", or orientation.  In science
jargon, the differentiation between the two spin states of an electron
cause by the external magnetic field is called "splitting the energy
degeneracy" of the states.

Left to itself, an electron in a magnetic field will orient itself so
that it is in the lower energy state.  If, however, we "pump" energy
into the system, then it is possible to "excite" the electron to the
higher energy state.    Specifically, an electron can interact with
("absorb") a photon that has the same energy as the energy difference
between the two spin states, and thus be "flipped" to the higher
energy state.  It turns out that for reasonable external magnetic
field strengths, the difference in energy between the two electron
spin states corresponds to the energy of photons in the microwave
regions of the electromagnetic spectrum.  EPR measures the absorption
of such microwave radiation, and thus "observes" the transition from
one spin state of an electron to another.

EPR only works on atoms or molecules that have what are called
"unpaired" electrons.  If all the electronic orbitals in an atom or
molecule contain two electrons (the most that can be put into any
given orbital), then the electrons in those pairs *must* have spins
that are oriented opposite to one another (due to a law known as the
Pauli Exclusion Principle).  If a such a system of paried spins is put
into a magnetic field, the energies of the two spin orientations are
"split", just as before, but now there are already electrons in both
the low-energy and high-energy state of each orbital.  The electron in
the low-energy state can't absorb a photon and be excited to the
higher energy state because that state is already occupied, and there
is "no room" for another electron.  If, however, an atom or molecule
has an electron orbital that contains a single, unpaired electron,
then the higher energy state of the orbital will be unoccupied, and
the low-energy electron can absorb a photon and be excited to that
state.

Important Disclaimer: Answers and comments provided on Google Answers are general information, and are not intended to substitute for informed professional medical, psychiatric, psychological, tax, legal, investment, accounting, or other professional advice. Google does not endorse, and expressly disclaims liability for any product, manufacturer, distributor, service or service provider mentioned or any opinion expressed in answers or comments. Please read carefully the Google Answers Terms of Service.

If you feel that you have found inappropriate content, please let us know by emailing us at answers-support@google.com with the question ID listed above. Thank you.
Search Google Answers for
Google Answers  


Google Home - Answers FAQ - Terms of Service - Privacy Policy