Hi. This one is really killing me for some strange reason:
Evaluate the following integral:
2
S[-x^2-2x]dx
-3
*Note* Pretend S is the integral sign and pretend [] is the absolute value sign.
Thanks for the help.

Recall that the definition of |x| is x if x>0 and -x if x<0.

You need to find the values of x such that -x^2 - 2x > 0 and -x^2 - 2x
< 0, then do a separate integral for each of these.

So I found the values of x to be -2 and 0. So I separated the problem
into three integrals. I ultimately got the answer to be 40/3. But my
answer manual says the answer is 28/3, though sometimes my manual has
errors. Which one is right this time? My answer or the manual's?
Ugghhhhh, I don't know why I'm so tripped over this one in
particular...

I got 28/3. For the integral from -3 to -2, I got 4/3, from -2 to 0 I
got 4/3, and from 0 to 2 I got 20/3.

Yay. I finally got it. Thanks for the help.