

Subject:
CalculusA Definite Integral Problem
Category: Reference, Education and News > Homework Help Asked by: jktallnycga List Price: $2.50 
Posted:
11 Dec 2005 12:06 PST
Expires: 11 Dec 2005 16:52 PST Question ID: 604443 
Hi. This one is really killing me for some strange reason: Evaluate the following integral: 2 S[x^22x]dx 3 *Note* Pretend S is the integral sign and pretend [] is the absolute value sign. Thanks for the help. 

There is no answer at this time. 

Subject:
Re: CalculusA Definite Integral Problem
From: kingalga on 11 Dec 2005 12:25 PST 
Recall that the definition of x is x if x>0 and x if x<0. You need to find the values of x such that x^2  2x > 0 and x^2  2x < 0, then do a separate integral for each of these. 
Subject:
Re: CalculusA Definite Integral Problem
From: jktallnycga on 11 Dec 2005 14:17 PST 
So I found the values of x to be 2 and 0. So I separated the problem into three integrals. I ultimately got the answer to be 40/3. But my answer manual says the answer is 28/3, though sometimes my manual has errors. Which one is right this time? My answer or the manual's? Ugghhhhh, I don't know why I'm so tripped over this one in particular... 
Subject:
Re: CalculusA Definite Integral Problem
From: kingalga on 11 Dec 2005 15:05 PST 
I got 28/3. For the integral from 3 to 2, I got 4/3, from 2 to 0 I got 4/3, and from 0 to 2 I got 20/3. 
Subject:
Re: CalculusA Definite Integral Problem
From: jktallnycga on 11 Dec 2005 16:52 PST 
Yay. I finally got it. Thanks for the help. 
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