If I am holding four clubs and I can draw two additional cards from a
full deck, what are the odds that at least one of the two will be a
club?

Can somebody explain the steps to get to the answer ?

P(at least 1 club) = 1 - P(no clubs)

P(no clubs) = P(1st card not club AND 2nd card not club)

If you're drawing from a full 52-card deck, then your odds of NOT
getting a club on you first draw are 3 out of 4 (3/4ths).

Your odds of not getting a clubs on the second card are also (pretty
close to) 3/4ths (the odds change very slightly because one card has
already been drawn from the deck, but the change is small, and too
complex to bother with).

So, the combined odds of not getting a clubs on either draw are:  3/4
x 3/4 = 9/16ths.

The odds of drawing a clubs are (1 - 9/16) = 7/16ths

which is a bit less than half, or more precisely 43.75%.


Let us know what sort of additional information you need to turn this
pretty informal explanation into a real answer.


paf