Google Answers Logo
View Question
 
Q: In-111 Decay ( No Answer,   6 Comments )
Question  
Subject: In-111 Decay
Category: Science > Physics
Asked by: hatb-ga
List Price: $25.00
Posted: 16 Sep 2002 14:19 PDT
Expires: 16 Oct 2002 14:19 PDT
Question ID: 65704
In-111 decays by electron capture to stable Cd-111 via a cascade of
two suceeding excited states of Cd-111 yielding photons of 173 and 247
keV. What is the angular  correlation of these photons and how is the
angular distribution characterized.

Request for Question Clarification by synarchy-ga on 19 Sep 2002 23:44 PDT
Well, it's been a really long time since quantum-mech, but, I think
that the following page, under the heading of "PAC technique" may give
you some clues.

http://www.physics.orst.edu/~platzer/ceram.html

Clarification of Question by hatb-ga on 20 Sep 2002 13:13 PDT
Synarchy -

What is unclear?
Answer  
There is no answer at this time.

Comments  
Subject: Re: In-111 Decay
From: rbnn-ga on 18 Sep 2002 20:55 PDT
 
A very interesting question. (I actually hadn't even known that "In"
meant "Indium" before tackling this one).

I've done a literature search on the web and the closest I can find is
question 7 of the homework assignment (from 1995) at
http://www.phys.washington.edu/~savage/class_cmu/part_cmu/assign0195.ps
and its answers http://www.phys.washington.edu/~savage/class_cmu/part_cmu/sol0195.ps
. However, this still isn't exactly what you are looking for.

General searches for "angular correlation" and "angular distribution"
mostly yielded various experimental papers measuring these in
different types of decay or scattering experiments.

Unfortunately I just don't have the quantum mechanics background to
tackle this one. Best of luck to you though (and any future
researcher).
Subject: Re: In-111 Decay
From: jahlon111-ga on 29 Sep 2002 15:31 PDT
 
Hey there. 

I took O-Chem, P-Chem, and T-Chem way back in 1981-1983, so my
knowledge on this front is most certainly outdated. But I can tell you
that the question (and its answer) must somehow be related to "the
Three Keys of J'lahn (V14.7)" --- here are the details:

Team:

Finally!!! Here it is, the long-awaited Version 14.7!!! Enjoy!!! 

:::the Three Keys of J'lahn:::
Copyright Jim Ward-Nichols 2002
All Rights Reserved

Key I::Aldehyde Reductase, w/Number, Aleph/Gimel/Kaph::
3=III=|||=111=7

Key II::Hyponitrite Reductase, w/Text, Beth/Daleth/Tzaddi::
11:11=||:||=22=HEXF=15=TheHornedOne=OMEGA=1

Key III::DNA-Directed DNA Polymerase, w/Communication, Yod/He/Vau::
11_111_11=II_III_II=||_|||_||=ALL_SEVEN

If you are going to copy the Three Keys and e-mail them to your
friends, please be sure to include the correct title (the Three Keys
of J'lahn), the version (this is 14.7), the author (Jim Ward-Nichols)
and the address of my website (http://jlwn111.home.att.net). Too many
times have I received copies of the Three Keys with other people's
names on them as author. I wish to maintain the purity and integrity
of this message. Please include the following notice:

Copyright Jim Ward-Nichols 2002
All Rights Reserved

'Nuff said. Until RC1 for Version 15.0, that is... 

I AM J'lahn.
The Most Holy Trinity Of The ALL_SEVEN Collective, Lodge No. 111
Newton/Lawrence [NW New Jersey / NE kANsas]
http://jlwn111.home.att.net
"the COMPLETED 111 experience of J'lahn: 1965-2000"
http://jlwn111.home.att.net/JHVH_tetragram_1111.jpg
http://jlwn111.home.att.net/111_3pillars.jpg
http://jlwn111.home.att.net/111_allseven_nu.jpg

"All my life I've awaited your coming and dreaded it."

"I knew soon."

"Now you listen to me. While I will admit to a certain cynicism, the
fact is I am a naysayer and hatchetman in the fight against violence.
I pride myself on taking a punch and I'll gladly take another because
I choose to live my life in the company of Gandhi and King. My
concerns are global. I reject absolutely pride, aggression, and
retaliation. The foundation of such a method is love."

"That such truths may seem trivial I am well aware."

"Show him My Children, show him the Pretty Marks."
Subject: Re: In-111 Decay
From: rbnn-ga on 11 Oct 2002 02:13 PDT
 
This question has almost expired and there remains no answer,
unfortunately. Although I do not plan to work on it, I would be very
interested in learning what the solution is; I'd also be interested in
learning where the question came from.

For whatever it's worth, this question rekindled my interest in
quantum mechanics; I read the Liboff textbook (which is superb) and am
starting on the book by Nielsen on Quantum Computation. My interest is
primarily quantum computation in fact.

However, even the terms used, "angular correlation" seem to be unusual
and I haven't found them in any of about 6 books on quantum mechanics
and nuclear physics that were in the local bookstore.
Subject: Re: In-111 Decay
From: rbnn-ga on 12 Oct 2002 11:43 PDT
 
Nuclear Condensed Matter Physics, Gunther Schatz and Alois Weidinger,
Wiley & Sons, 1996, has a detailed discussion of angular correlation
computations in chapter 5. They go through an example on page 66 of
computing the angular correlation for the gamma-gamma cascade in
Co-60, which decays two Ni-60 sending out two photons at 2.5 and 1.33
MeV.

Formula 5.19 on page 71 has a formula for more general angular
correlation. I'm not sure exactly how to apply this to the In-111
case, however, but perhaps that reference will be helpful to you.
Subject: Re: In-111 Decay
From: discgopher1-ga on 15 Jan 2003 23:32 PST
 
Hi,

Filossofov et. al. measure the angular correlation between the 173 and
247 (245?) KeV gammas.  Their paper (in Russian) is at:
http://www1.jinr.ru/Preprints/2001/p6-2001-112.pdf

There may be more info in:

Rinneberg At. Energy Rev,. vol. 17 pg. 477 (1979)
Subject: Re: In-111 Decay
From: bbrendon-ga on 06 Feb 2003 16:58 PST
 
.

Important Disclaimer: Answers and comments provided on Google Answers are general information, and are not intended to substitute for informed professional medical, psychiatric, psychological, tax, legal, investment, accounting, or other professional advice. Google does not endorse, and expressly disclaims liability for any product, manufacturer, distributor, service or service provider mentioned or any opinion expressed in answers or comments. Please read carefully the Google Answers Terms of Service.

If you feel that you have found inappropriate content, please let us know by emailing us at answers-support@google.com with the question ID listed above. Thank you.
Search Google Answers for
Google Answers  


Google Home - Answers FAQ - Terms of Service - Privacy Policy