3 people go go a hotel. They are charged $30 at the desk. They each
chip in $10 and go up to their rooms (this was a long time ago when
rooms were cheap). The hotel manager then remembers that there is a
special, and 3 rooms rent for only $25. So he gives the bellhop 5, $1
bills to take to the people. He gives $1 to each of them, and he keeps
2 (as a tip). Each of the 3 had then paid 10-1 = $9 for the room. 3 x
9 = $27, plus the two the bellhop kept makes $29. What happened to the
last dollar? ...
Looking at this from another way, each of the people paid $9.666.. , 9
for the room plus one third of $2. But 3 x 9.66.. is not 10, and there sure
as heck are 30 real whole dollars to account for.
What gives?? |
Request for Question Clarification by
rainbow-ga
on
24 Feb 2006 11:59 PST
Does this explanation answer your question?
"The facts in this riddle are clear: There is an initial $30 charge.
It should have been $25, so $5 must be returned and accounted for. $3
is given to the 3 friends, $2 is kept by the bellhop - there you have
the $5. The trick to this riddle is that the addition and subtraction
are done at the wrong times to misdirect your thinking - and quite
successfully for most. Each of the 3 friends did indeed pay $9, not
$10, and as far as the friends are concerned, they paid $27 for the
night. But we know that the clerk will tell us that they were charged
only $25 and when you add the $3 returned with the $2 kept by the
bellhop, you come up with $30."
The Missing Dollar Riddle
http://www.justriddlesandmore.com/missingsol.html
Regards,
Rainbow
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