Hello,

I am looking for a good example of code to collect random bits on
mouse movements.  I am using Visual Basic 6. By moving mouse on the
form I need to collect about 100 bits of random numbers on the timer
(firing every second or less). All 100  bits I need to write to the
collection (as a string?). I will really appreciate if somebody can do
it for me.

Thanks,
BV6

If you want to obtain the mouse position many times a second, you
could use the 'mouse move'  procedure.
ie. in the code for the 'form', select 'MouseMove'.    That will give
you a procedure which gives you the X and Y coordinates of the mouse
cursor on the form.  This procedure will be called many times a second
(as long as the mouse is moving), so there's no need to use a timer. 
But if you wanted to use a timer and only check the mouse position a
specified number of times a second, you could set global variables to
the values of the mouse's X & Y position, then use these in the timer
function (eg. you could add the X & Y values to an array of X & Y
values in the every tenth of a second or so in the timer function).

When you say you want to write '100 bits to a collection', do you
actually mean bits (eg. binary digits, ie. 1 or 0?) or just 100
numbers?
To add 100 numbers to a collection, you could create an ARRAY of
integers. eg. Dim numbers(100) as integer
The mouse movements may not be very random though, especially if the
mouse is moved only very slowly.  Also, the maximum size of the
numbers you get will depend on the size of the form.  If you want the
numbers to be a bit more random, you could use the randomize function
(eg. seed the random number generator with the mouse positions), then
use the rnd function (to generate random numbers).
To get a 'random bit' from the mouse position (if you mean 1 or 0),
you could say something like, if the X mouse position is even, set a
variable to 0, otherwise set a variable to 1.  eg. if x mod 2=0 then
number=0 else number=1

If the above isn't quite what you meant, please give further details
on what you meant and I'll try and give a better method

Thank you sherlockh for your help.  I think I got a clear idea what
should I do.
I can not figure out here how to rate a question, but I would give you
5 stars for the comment.  Thank you!

He generously answered your question for free as a comment, which is
why you cannot rate his answer; though, come to think of it, someone
should propose that as an option to the Google! Answers management.

Additionally, most security-focused programs get their randomized
input from users by examining the time between inputs; it is something
that can be measured very very precisely and is in such small
increments that it is impossible (for all intents and purposes) to
duplicate.

The direction of movement, of course, can be added as additional
randomness per movement, but I think it is probably best to get all
your numbers from timings.

I agree with sherlockh-ga's approach on how to accomplish the program,
and also that, for a (free) comment, bv6-ga is getting quite a deal on
his Question.

However, the Question does state that s/he is looking for "a good
example of code," and since it's priced at $50, I'd say that if
sherlockh-ga's Comment were an Answer, it would fall somewhat short of
completely answering the question since there is no code given.

Perhaps I could whip this program up in VB6 along the lines of what
sherlockh-ha has outlined, and then post the source code as an Answer.

Would you be interested in this, or has the Comment already helped you
out enough to where you wouldn't feel the need to pay $50?

Note: This thorough technical design description vs. "live code"
answer is a common dilemma when answering technical questions. Yes,
sherloch-ga basically gives you the design on how to do it, which, for
a Comment, is more than you could ask for, but there's no actual code
which the fairly priced quesion asks for.

A single answer which gives BOTH a thorough technical design
descripion and live, working source code would be worth more than $50
in my opinion, although that doesn' mean you won' get it, especially
with the high quality of free comments.

~omniscienbeing-ga